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hodyreva [135]
4 years ago
11

all possible numbers that when replaced with the "?" in the set of ordered pairs {(3, 4), (–2, –5), (?, 0)} would create a funct

ion.
Mathematics
1 answer:
irina [24]4 years ago
4 0
? can be any number except for 3 or -2 as it is already used in (3,4), (-2,-5)
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Solve the following equations. You will need to show your work in order to receive full credit.
vodomira [7]

Hello from MrBillDoesMath!

Answer:   x =  10 for 4x - 8 = 32

               x = -5  for 2(x-5) = -20

Discussion:

------------------------------

4x - 8 = 32    (*)

Add 8 to both sides:

4x - 8 + 8 = 32 + 8 =>

4x = 40 =>

x = 10


-----------------------------------------------

2(x-5) = 2x - 2(5)  =>

2x - 10 = -20 (**)

Add 10 to each side of (**):


2x - 10 + 10 = -20 + 10 =>

2x = -10

x = -5




Thank you,

MrB


7 0
4 years ago
Scores on the SAT Mathematics test are believed to be normally distributed. The scores of a simple random sample of five student
AysviL [449]

Answer:

The mean calculated for this case is \bar X=584

And the 95% confidence interval is given by:

584-2.776\frac{86.776}{\sqrt{5}}=476.271    

584+2.776\frac{86.776}{\sqrt{5}}=691.729    

So on this case the 95% confidence interval would be given by (476.271;691.729)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=584

The sample deviation calculated s=86.776

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that t_{\alpha/2}=2.776

Now we have everything in order to replace into formula (1):

584-2.776\frac{86.776}{\sqrt{5}}=476.271    

584+2.776\frac{86.776}{\sqrt{5}}=691.729    

So on this case the 95% confidence interval would be given by (476.271;691.729)    

3 0
3 years ago
State the null and alternative hypotheses to test if the population represented by Sample 1 has a mean that is 2.0 units higher
avanturin [10]

Answer:

Null Hypothesis, H_0 : \mu_A-\mu_B = 2.0 units  or  \mu_D = 2.0 units

Alternate Hypothesis, H_A : \mu_A-\mu_B\neq 2.0 units  or  \mu_D\neq 2.0 units

Step-by-step explanation:

We are given the following data below and we have test if the population represented by Sample 1 has a mean that is 2.0 units higher than the population represented by Sample 2;

Pair : 1 2 3 4 5 6 7

Sample1 : 5 6 10 3 6 7 8

Sample2 : 4 4 3 5 5 5 3

Let \mu_A = population mean represented by Sample 1

\mu_B = population mean represented by Sample 2

\mu_D = population mean matched-pair differences for Sample 1 - Sample 2

So, Null Hypothesis, H_0 : \mu_A-\mu_B = 2.0 units  or  \mu_D = 2.0 units

Alternate Hypothesis, H_A : \mu_A-\mu_B\neq 2.0 units  or  \mu_D\neq 2.0 units

Here null hypothesis states that the population represented by Sample 1 has a mean that is 2.0 units higher than the population represented by Sample 2.

On the other hand, alternate hypothesis states that the population represented by Sample 1 has a mean that is not 2.0 units higher than the population represented by Sample 2.

6 0
4 years ago
A bank has a special vault for valuable items . It has 3 dials that operate the combination . The first dial has the numbers fro
SCORPION-xisa [38]

Answer:

There are 67,600 possible combinations for this vault.

Step-by-step explanation:

First dial: 100 possible values

Second dial: 26 possible values

Third dial: 26 possible values.

How many possible combinations are there for this vault?

Multiplication of these values. So

100*26*26 = 67600

There are 67,600 possible combinations for this vault.

7 0
3 years ago
Find the diameter of the object.<br><br> diameter: __ cm
VARVARA [1.3K]
Question unclear. no object to find diameter of
8 0
3 years ago
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