All categories

2 years ago

What heat transfer is Christmas lights radiation or convention or conduction

Mathematics

2 answers:

Firdavs [7]2 years ago

7 0

Answer:

The heat from the sun or heat released from the filament of a light bulb is the example of radiation.

mamaluj [8]2 years ago

4 0

I think the answer is Radiation. Sorry if I’m wrong!

You might be interested in

Hello can u please help

Andrei [34K]

y = mx + b

-3 = -2(-5) + b

-3 = 10 + b

-13 = b

y = -2m - 13

The line would pass through -13 on the y-axis and it would go down 2 and move to the right 1 for every new point.

Hope this helps! ;)

6 0

2 years ago

Read 2 more answers

14.2 as a mixed number.

krek1111 [17]

I think its 14 1/5 (?)

7 0

2 years ago

Read 2 more answers

Help me out pleaseeee ASAP :(

prisoha [69]

Answer:

Your answer is RSP. THE 3RD one

3 0

3 years ago

The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.

VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

$\int\limits^2_{-1} {(f(x) - g(x))} \, dx$

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx$

We know that:

$\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}$

$\int\limits^{}_{} {1} \, dx = x$

$\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}$

Then our integral is:

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2} + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3} + (-1) - \frac{(-1)^2}{2} )$

The right side is equal to:

$(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6$

The bounded area is 5 + 5/6 square units.

3 0

2 years ago

Solve the system of equations by substitution: y = x - 2

gizmo_the_mogwai [7]

Step-by-step explanation:

y = x - 2

x + y = 12

Substitute the first expression for y into the second equation.

x + (x - 2) = 12

2x - 2 = 12

2x = 14

x = 7

Now plug into either equation to find y.

y = 7 - 2

y = 5

So the solution is (7, 5).

4 0

2 years ago