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melomori [17]
3 years ago
7

3y+2=5(y-6) please help :)

Mathematics
2 answers:
grigory [225]3 years ago
4 0
In this problem, y = 16!
Alex777 [14]3 years ago
3 0
Y = 16 

=3y+2=5(y−6)

=3y+2=5y−30

=3y+2−5y=5y−30−5y

<span><span><span>=−<span>2y</span></span>+2</span>=<span>−30

</span></span>=−2y+2−2=−30−2

<span><span>=−<span>2y</span></span>=<span>−32

</span></span>=−2y−2=−32−2

<span>y=<span>16</span></span>
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Answer:

Step-by-step explanation:

f(x)=2(x-2)²-5

f(x)=2(x²-4x+4)-5

f(x)=2x²-8x+3

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3 years ago
Which one is correct ?
mina [271]

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Answer choice B

Step-by-step explanation:

The measures of angles on touching the opposite sides of the circles are always half the lengths of their respective arc. 126/2=63, or answer choice B. Hope this helps!

3 0
3 years ago
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Please help i will give brainliest
Lilit [14]

Answer:

c

Step-by-step explanation:

7 0
3 years ago
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

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By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

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5 0
3 years ago
I need help ASAP
GaryK [48]

Answer:

500

Step-by-step explanation:

Define listed price = C

Based on the term, to have the balance on both plan, the equation is 30+90%C = 80+80%C

  1. 30+0.9C=80+0.8C
  2. 0.1C=50
  3. 1C = 500
6 0
3 years ago
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