Question

What is an equation of the line that passes through the point (5,1)(5,1) and is parallel to the line x+y=9x+y=9?

Answer 1

Answer:

Step-by-step explanation:

Use the point-slope formula.

y - y_1 = m(x - x_1)    you have :  x_1 =5  and  y_1 =1

m the slope  m= -1 (same slope for the line : x+y=9 because this lines are parallel and you can write y=-x+9

an equation for this line is : y-1 = -(x-5)