What is an equation of the line that passes through the point (5,1)(5,1) and is parallel to the line x+y=9x+y=9?
1 answer:
Answer:
Step-by-step explanation:
Use the point-slope formula.
y - y_1 = m(x - x_1) you have : x_1 =5 and y_1 =1
m the slope m= -1 (same slope for the line : x+y=9 because this lines are parallel and you can write y=-x+9
an equation for this line is : y-1 = -(x-5)
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Suppose we let 
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Also, recall the double angle identity for cosine:
So, we can rewrite and compute the integral using the substitution, as
y = mx+b
(5-8)/(9-0) = -1/3 which is m
solve point slope to find slope intercept by using one of the points (0,8)
y-y1=m(x-x1)
y-8 = -1/3(x-0)
y-8 = -1/3x
Answer: y = -1/3x + 8
Answer:
I really want to help you but I am really confused with those topics. I am very sorry.
Step-by-step explanation:
1000 + 5027445423 = 5027446423
