A local board of education conducted a survey of residents in the community concerning a property tax levy on the coming local b
allot. They randomly selected 850 residents in the community and contacted them by telephone. Of the 850 residents surveyed, 410 supported the property tax levy. Let p represent the proportion of residents in the community that support the property tax levy. How large a sample n would you need to estimate p with margin of error 0.04 with 95% confidence? Assume that you don't know anything about the value of p. n = 601 n = 423 n = 1037 n = 256
Uhm, I'm pretty new to expanded form but I think it's something like: (3 × 1/10) + (1 × 1/100) + (6 × 1/1000) You can also write it as: 0.3 + 0.01 + 0.006 Let me know if you need working or anything!
