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pogonyaev
3 years ago
15

Use the data in the table. Find the median of the data. A) 11 B) 12 C) 13 D) 15

Mathematics
1 answer:
Sphinxa [80]3 years ago
8 0
It would be 12 since the middle numbers are 11 and 13 you take the number in the middle
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The dot plot represents a sampling of ACT scores:
Troyanec [42]

The data from a dot plot can be analyzed to find the five number summary, from which a box plot can be constructed

The correct option for the details of the box plot that represents the dot plot data is;

<em>Box plot </em><em>titled ACT Score with a minimum of </em><em>18</em><em>, quartile 1 of </em><em>21</em><em>, median of </em><em>22</em><em>, quartile 3 of </em><em>23</em><em>, and maximum of </em><em>25</em>

The process of deriving the five number summary of the box plot above is as follows;

Known:

The data from the dot plot can be expressed in increasing order for analysis of a box plot as follows;

18, 19, 19, 19, 21, 21, 21, 21, <u>22, 22</u>, 22,22, 23, 23, 23, 24, 24, 25

The number of data points in the statistics, n = 18

Unknown:

The five number summary

Method:

Finding the five number summary as follows;

The minimum value = 18

The maximum value = 25

  • The first quartile, inclusive of the median Q₁ = The middle number of the lower half {18, 19, 19, 19, 21, 21, 21, 21, <u>22}</u> = The (9 + 1)/2 th term

∴ Quartile 1 = Q₁ = 5th term = 21

  • The second quartile, Q₂ = The median (the middle number) = (22 + 22)/2 = 22 = Quartile 2

Quartile 2 = 22

  • The third quartile = The middle number of the upper half {<u>22</u>, 22,22, 23, 23, 23, 24, 24, 25} = Quartile 3 = 23

Quartile 3 = 23

Combining the above 5 number summary, the correct option for the box plot representing the dot plot data, is therefore;

Box plot titled ACT Score with a minimum of 18, quartile 1 of 21, median of 22, quartile 3 of 23, and maximum of 25

Learn more about box and whiskers, and dot plots here;

brainly.com/question/4002977

7 0
2 years ago
A tunnel must be made through a hill. As a result, a surveyor and an engineer create a sketch of the area. The sketch, displayed
Anastasy [175]

Answer:

498 m

Step-by-step explanation:

The AAA theorem states that triangles are similar if all three corresponding angles are equal.

1. Compare triangles FHS and ILS

(a) Reason for similarity

∠F = ∠I = 90°

∠S is common.

∴ ∠H = ∠L

(b) Calculate SL

\begin{array}{rcl}\dfrac{SF}{SH} & = & \dfrac{SI}{SL}\\\\\dfrac{225}{380} & = & \dfrac{225 + 475}{SL}\\\\225SL & = & 380 \times 700\\& = & 266000\\SL & = & \textbf{1182 m}\\\end{array}

2. Compare triangles ILS and GLE

(a) Reason for similarity

∠I = ∠G = 90°

∠L is common.

∴ ∠S = ∠E

(b) Calculate LE

\begin{array}{rcl}\dfrac{IS}{GE} & = & \dfrac{LS}{LE}\\\\\dfrac{700}{180} & = & \dfrac{1182}{LE}\\\\700LE & = & 180 \times 1182\\& = & 212800\\LE & = & \textbf{304.0 m}\\\end{array}

3. Calculate EH

               LE + EH + HS = LS

304.0 m + EH + 380 m = 1182 m

                  EH + 684 m = 1182 m

                                 EH = 498 m

The distance from E to H is 498 m.

 

5 0
3 years ago
What is the solution set of the quadratic inequality x²-5≤0
mart [117]

Answer:

X² - 5 = 0

x² = 5

square on both side

x = 5²

x = 25

May mine aswer might be wrong please retrify but as per my point of view it will be write

5 0
3 years ago
Joey puts 25% of his allowance into savings each week. If last week he put 10$ in savings, what was his allowance last week?​
GrogVix [38]

Answer:

$40

Step-by-step explanation:

25% is 1/4.

If 10 is 1/4 of the full amount, then you take 10 and multiply by 4 to get the full amount.

10 times 4 equals 40.

7 0
3 years ago
1. The sum of the angles is 90° The difference between twice the larger angle and the smaller
Ostrovityanka [42]

Answer:

\displaystyle 25°\:and\:°65

Step-by-step explanation:

{90° = m∠1 + m∠2

{105° = 2m∠1 - m∠2

_______________

\displaystyle \frac{195°}{3} = \frac{3m∠1}{3} \\ \\ 65° = m∠1

All you have left to do is this:

\displaystyle 25° = -65° + 90°

So, your two angle measures are \displaystyle 25°\:and\:°65.

I am joyous to assist you anytime.

5 0
3 years ago
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