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2 years ago

Four tanks each had 54 litres and 750ml. what is their total capacity in litres

Mathematics

2 answers:

Furkat [3]2 years ago

5 0

Answer: 219 I beleive

Step-by-step explanation: 54(4)+(.750)4=219

ira [324]2 years ago

4 0

Answer:

each tank = 54 + (750÷ 1000) liter = 54.75L

so the capacity of the four tanks = 4x 54.75 = 219litre

Step-by-step explanation:

1) change 750 ml int litre which is equal 750÷1000 = 0.75L

2) add 54 +0.75

3) multiply 4 by 54.75 = 219L

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Zadanie optymalizacyjne z matematyki. Proszę o rozwiązanie i wyjaśnienie

Yakvenalex [24]

Volume of the pyramid:

$V=\dfrac{s^2h}3$

Perimeter of the cross-section:

$40=\sqrt2\,s+2\sqrt{\dfrac{s^2}2+h^2}=\sqrt2\left(s+\sqrt{s^2+2h^2}\right)$

$\implies h=\sqrt{\dfrac{(20\sqrt2-s)^2-s^2}2}=\sqrt{400-20\sqrt2\,s}$

Area of the cross-section:

$P=\dfrac12(\sqrt2\,s)h=\dfrac{sh}{\sqrt2}$

$\implies P=\dfrac{s\sqrt{400-20\sqrt2\,s}}{\sqrt2}=s\sqrt{200-10\sqrt2\,s}$

First derivative test:

$\dfrac{\mathrm dP}{\mathrm ds}=\dfrac{20\sqrt2-3s}{\sqrt{4-\dfrac{\sqrt2}5s}}=0\implies s=\dfrac{20\sqrt2}3$

Then the height of the cross-section/pyramid is

$h=\sqrt{400-20\sqrt2\,s}=\dfrac{20}{\sqrt3}$

The volume of the pyramid that maximizes the cross-sectional area $P$ is

$V=\dfrac{\left(\frac{20\sqrt2}3\right)^2\frac{20}{\sqrt3}}3=\dfrac{16000}{27\sqrt3}$

5 0

3 years ago

Which line has a slope of -3/4 and y-intercept of 3/2

aksik [14]

Y=mx+b
m=slope
b=yintercept
slope=-3/4
yintercept=3/2

y=-3/4x+3/2

it could also be written
3x+4y=6

8 0

3 years ago

Read 2 more answers

What is m in 4/5m=2/9 is it 5/18

Romashka [77]

$\frac{4}{5} m = \frac{2}{9} \\ \\ \frac{4m}{5} = \frac{2}{9} \\ \\ 4m = \frac{2}{9} \times 5 \\ \\ 4m = \frac{10}{9} \\ \\ m = \frac{10}{9 \times 4} \\ \\ m = \frac{10}{36} \\ \\ m = \frac{5}{18} \\ \\$

The final result is: m = 5/18 or 0.2778.

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%28-5x%5E3%29%5E3%2F%2810x%5E5%29%5E2" id="TexFormula1" title="(-5x^3)^3/(10x^5)^2" alt="(-5x^

marta [7]

Answer:

$-\frac{5}{4x}$

Step-by-step explanation:

<h2> $\left(-5x^3\right)^3\div \left(10x^5\right)^2$ </h2><h2> $\frac{-5^3x^9}{\left(10x^5\right)^2}$ </h2><h2> $\frac{-5^3x^9}{10^2x^{10}}$ </h2><h2> $\frac{-5^3x^9}{5^2\cdot \:2^2x^{10}}$ </h2><h2> $\frac{-5x^9}{2^2x^{10}}$ </h2><h2> $\frac{-5}{2^2x}$ </h2>

$-\frac{5}{4x}$

- hope it helps! -

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3 0

1 year ago

Easy question, please help

stepladder [879]

Step-by-step explanation:

All you need to do is divide cost by mile since they already factored in the additional $3 for you.

1. 8/5 = $1.60

2. 11/8 = $1.375 = $1.38

3. 23/20 = $1.15

6 0

2 years ago

Four tanks each had 54 litres and 750ml. what is their total capacity in litres ​

Four tanks each had 54 litres and 750ml. what is their total capacity in litres