The cost of the entrance would be 7.5$, because 2.50$ x 6 equals 15.
Let’s multiply 6 x 2 to get twelve, and if six rides are 15$, that would be 30$ for twelve rides. But we still have three more.
2.50 x 3 would be 7.5$, and if we add that to 30$, we would get 37.5$.
With entry fee though, we would add 37.5$ to
7.5$, and so it would be 45$ on the dot.
Your answer would be 37.5$ without entry fee, and 45$ with entry fee.
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Answer:
(a - b)^2 = 49 - 4b^2 +2ab
Step-by-step explanation:
Given: a^2 + b^2 = 7b (assuming A is really “a”)
b^2 + (2b - a)^2 = 7^2
Find; (a - b)^2
Plan: Use Algebraic Manipulation
Start with b^2 + (2b - a)^2 = 7^2 =>
b^2 + 4b^2 - 4ab + a^2 = 49 by expanding the binomial.
a^2 + b^2 + 4b^2 - 4ab = 49 rearranging terms
a^2 + b^2 -2ab - 2ab + 4b^2 = 49 =>
a^2 - 2ab + b^2 = 49 - 4b^2 +2ab rearranging and subtracting 4b^2 and adding 2ab to both sides of the equation and by factoring a^2 - 2ab + b^2
(a - b)^2 = 49 - 4b^2 +2ab
Double Check: recalculated ✅ ✅
(a - b)^2 = 49 - 4b^2 +2ab