Answer:
answer is 25
Step-by-step explanation:
EKJ = 90, same as JHF, and EJK is 65 (because EJF =115 and 180-115=65
65+90=155
180-155=25
27% + 18% = 45%
Hope you understand problems like this better in the future
2.6 gallons per hour x 16 hours = 41.6 gallons
Assuming P (usually written in upper case) represents a force normal to a given cross section.
If a point load is applied to any point of the section, stress concentration will cause axial stress to vary.
The context of the question considers the uniformity of axial stress at a certain distance away from the point of application (thus stress concentration can be neglected).
If a force P is applied through the centroid, sections will be stressed uniformly. However, if the force P is applied at a distance "e" from the centroid, the equivalent load on the section equals an axial force and a moment Pe. The latter causes bending of the member, causing non-uniform stress.
If we assume A=(uniform) cross sectional area, and I=moment of inertia of the section, then stress varies with the distance y from the centroid equal to
stress=sigma=P/A + My/I
where P=axial force, M=moment = Pe.
Therefore when e>0, the stress varies across the section.
Answer:
4.2
Step-by-step explanation:
its asymmetrical
