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ra1l [238]
3 years ago
14

Classify the expression: −2x2 + 11

Mathematics
1 answer:
lianna [129]3 years ago
8 0

Answer: Quadratic

Step-by-step explanation:

Anything with 0 degree's: Constant

Anything with 1 degree: Linear

Anything with 2 degree's: Quadratic

Anything with 3 degree's: Cubic

Anything with 4 degree's: Quartic

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What is the solution of the system x - 3y= -13​
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There should be one more equation

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What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0
2 years ago
An insurance company divides its policyholders into low-risk and high-risk classes. 60% were in the low-risk class and 40% in th
AleksAgata [21]

Answer:

a). 0.294

b) 0.11

Step-by-step explanation:

From the given information:

the probability of the low risk = 0.60

the probability of the high risk = 0.40

let C_o represent no claim

let C_1 represent 1 claim

let C_2 represent 2 claim :

For low risk;

so, C_o  = (0.80 * 0.60 = 0.48),  C_1 =  (0.15* 0.60=0.09),   C_2 = (0.05 *  0.60=0.03)

For high risk:

C_o  = (0.50 *  0.40 = 0.2),  C_1 =  (0.30 *  0.40 = 0.12) ,   C_2 = ( 0.20 *  0.40 = 0.08)

Therefore:

a),  the probability that a randomly selected policyholder is high-risk and filed no claims can be computed as:

P(H|C_o) = \dfrac{P(H \cap C_o)}{P(C_o)}

P(H|C_o) = \dfrac{(0.2)}{(0.48+0.2)}

P(H|C_o) = \dfrac{(0.2)}{(0.68)}

P(H|C_o) = 0.294

b) What is the probability that a randomly selected policyholder filed two claims?

the probability that a randomly selected policyholder be filled with two claims = 0.03 + 0.08

= 0.11

7 0
3 years ago
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