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Which data set could be represented by the boxplot shown? (1 point)

lidiya [134]

The second data set represents the boxplot because in the box plot the measure of statistics is the same as the data set option second is correct.

<h3>What is the box and whisker plot?</h3>

A box and whisker plot is a method of abstracting a set of data that is approximated using an interval scale. It's also known as a box plot. These are primarily used to interpret data.

We have given a data set and a box plot shown in the picture.

From the boxplot we can see:

Minimum value = 2

Q1 = (2+4)/2 = 3

Median = (4+6)/2 = 5

Q3 = (8+10)/2 = 9

Maximum value = 10

The second data set:

{2, 3, 3, 4, 5, 5, 8, 10, 10}

Minimum value = 2

Q1 = (2+4)/2 = 3

Median = (4+6)/2 = 5

Q3 = (8+10)/2 = 9

Maximum value = 10

Thus, the second data set represents the boxplot because in the box plot the measure of statistics is the same as the data set option second is correct.

Learn more about the box and whisker plot here:

brainly.com/question/3209282

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2 years ago

Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1

defon

I'm guessing the series is supposed to be

$\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}$

By the ratio test, the series converges if the following limit is less than 1.

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|$

The first $n$ terms in the numerator's denominator cancel with the denominator's denominator:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|$

$|x^n|$ also cancels out and the remaining factor of $|x|$ can be pulled out of the limit (as it doesn't depend on $n$ ).

$\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0$

which means the series converges everywhere (independently of $x$ ), and so the radius of convergence is infinite.