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mash [69]
3 years ago
11

Round 4806 to the nearest 1000?

Mathematics
2 answers:
grandymaker [24]3 years ago
7 0
If you want to round to the nearest thousand, you cannot look at the thousands place to round.  You will have to look at the number in the hundreds place.  The rules of rounding are 
<em>5 and above-round up.  Example-2743.  7 is greater than 5, so 2743 rounded to the nearest thousand is 3000.
</em>
<em>4 and below-round down.  Example-4390.  Three is less than 5, so 4390 rounded to the nearest thousand is 4000.  
</em>
Apply these rules to your problem.  8 is greater than 5.  So we will round up.  You get 5000.<em>

</em>
ira [324]3 years ago
7 0
<em>Look At The Picture.</em>







Good Luck!

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murzikaleks [220]
F(x) = (x² - 3x - 10)(x + 4) becomes (x - 5)(x + 2)(x + 4) when completely factored. Now set each binomial equal to zero. 

x - 5 = 0
x = 5

x + 2 = 0
x = - 2

x + 4 = 0
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Your zeros are at x = - 4, - 2, and 5. Or at (- 4, 0), (- 2, 0), and (5, 0). 
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4 years ago
Read 2 more answers
Complete the statements.
spayn [35]

Answer:

1. 30

2. 150

Step-by-step explanation:

3tan^2(x)-1 =0

Lets assume tan(x) = u

3u^2(x)-1 =0

Now we solve for 'u'

add 1 on both sides

3u^2(x) =1, divide both sides by 3

u^2 = \frac{1}{3}

Take square root on both sides

u = +-\frac{1}{\sqrt{3} }

We replace tan(x) for 'u'

tan(x) = +-\frac{1}{\sqrt{3} }  

x = 30 because tan(30) =+\frac{1}{\sqrt{3} }  in first quadrant

      x = 30      (tan is positive in first quadrant)

tan(x) =-\frac{1}{\sqrt{3} }                                                    

  x = 150 because tan(150) =-\frac{1}{\sqrt{3} }  in second quadrant

     tan is negative in second quadrant




4 0
4 years ago
Need help on this? Please help
Marysya12 [62]

parallel: g(x) = -5/3x + 1

perpendicular: h(x) = 3/5x - 5

neither: j(x) = 2x + 3

7 0
3 years ago
Find the lateral surface area of this
Allushta [10]

Answer:226.2

Step-by-step explanation

Lateral= 2πrh

H=12

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2*π*3*12=226.19

Round to nearest 10th is 226.2

6 0
3 years ago
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