Answer:
Hence the probability of the at least 9 of 10 in working condition is 0.3630492
Step-by-step explanation:
Given:
total transistors=100
defective=20
To Find:
P(X≥9)=P(X=9)+P(X=10)
Solution:
There are 20 defective and 80 working transistors.
Probability of at least 9 of 10 should be working out 80 working transistors
is given by,
P(X≥9)=P(X=9)+P(X=10)
<em>{80C9 gives set of working transistor and 20C1 gives 20 defective transistor and 100C10 is combination of shipment of 10 transistors}</em>
P(X≥9)=
<em>(Use the permutation and combination calculator)</em>
P(X≥9)=(231900297200*20/17310309456440)
+(1646492110120/17310309456440)
P(X≥9)=0.267933+0.0951162
P(X≥9)=0.3630492
Answer:A
Step-by-step explanation:
For SSS you need all sides
Given:7-x-5=x+2
1)combine like terms
2-x=x+2
2)Isolate the variable
-x=x+2-2
3)move x to the left
-x-x=0
4)combine like terms
-2x=0
5)Divide
X=0
In order to arrive at the answer, take the total (251) and subract it by 148. J = 103
Answer: Base numbers are the number of units, or numbers, we use in our counting system, also called a number system. The most common base number is ten because the digits 0-9 are used in the number system. In other words, whenever we want to tell a number to someone we don't use any numbers besides 0-9. If it was a base-5 number system we would only use five different digits, like 0-4.
Step-by-step explanation: