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3 years ago

3(1-3x)=2(-4x+7) solve

Mathematics

2 answers:

Rudiy273 years ago

8 0

Simplify the left side.

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3−9x=2(−4x+7)

Simplify the right side.

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3−9x=−8x+14

Move all terms containing x

to the left side of the equation.

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3−x=14

Move all terms not containing x

to the right side of the equation.

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−x=11

Multiply each term in x=−11

by −1

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x=−11

Hope this helps!

ivann1987 [24]3 years ago

6 0

First you use the distributive property. So, 3 times 1 and 3 times -xx = 2 times -4x and 2 times 7. This becomes 3-9x = -8x+14. Subtract 3 from both sides and add 8x to both sides and you get -x=11, so x=-11

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The expression (y-20)(y5)3 is equivalent to ya. What is the value of a?

Leno4ka [110]

Answer:

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Step-by-step explanation:

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$(y-20)(y^5)^3$

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which means we have

$(y-20)*y^{15}\\\\y^{16}-20y^{15}=ya\\\\*y^{15}-20y^{14}=a$

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3 years ago

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Elena-2011 [213]

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4 0

3 years ago

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SVETLANKA909090 [29]

$y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\$

$\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\$

This shows that $y' = y$ is true when $y = e^x$

-----------------------

Note 1: A more general solution is $y = Ce^x$ for some constant C.
Note 2: It might be tempting to say the general solution is $y = e^x+C$ , but that is not the case because $y = e^x+C \to y' = e^x+0 = e^x$ and we can see that $y' = y$ would only be true for C = 0, so that is why $y = e^x+C$ does not work.

6 0

3 years ago

How can I solve (n+1) x 2= 10 <br> Please someone answer :(

Ray Of Light [21]

(n+1)x 2=10
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2n=8
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4 0

4 years ago

Read 2 more answers

Pick 3 cards from a standard 52-card deck. Find the P(of at least 1 red card).

kkurt [141]

Answer:P(BBR) = 1/2 × 25/51 × 26/50 = 13/102 if cards are not replaced.

P(RBB) = 1/2 × 26/51 × 25/50 (simplified 1/2) = 13/102

P(BRB) = 1/2 × 26/51 ×25/50 (simplified 1/2) = 13/102

Step-by-step explanation: P(B) at first step is 26 cards out of a possible 52 therefore 26/52 (or simplified 1/2). We then have 25 black cards left out of a possible 51 therefore 25/51. The final card then has to be red to meet the criteria, we have 26 red cards still out of a possible 50 therefore 26/50.

This would be an example of binomial probability as at each step there are only 2 options R or B.

8 0

3 years ago