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2 years ago

Y=x+1 3x-2y=5 solve using substitution

2 answers:

6 0

Answer: (4, 5)
Work:
Substitute the y in the second problem with y=x+1
3x-2(x+1)=5
3x-2x+1=5
x=4
Now solve for y
y=4+1
y=5

tatuchka [14]2 years ago

6 0

1st: You plug x+1 in for the value of y of the equation 3x-2y=5
2nd: Then you solve the equation 3x-2(x+1)=5
You will need to distribute the -2 into the x and 1 that is in the parentheses
You will then get 3x-2x-2=5
Then combine like terms which are 3x and -2x
You get x-2=5, then you will just add the 2 to both sides so then you will get x=7
3rd:Then you substitute the 7 that you just got in for the value of x for the equation y=x+1
4th:The equation would now be y=(7)+1
So then you will just add 7 and 1 together and you get y=8
*Your final answer is (7,8)*

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lawyer [7]

Answer:

The difference quotient for $f(x)=3x^2$ is $3 h + 6 x$ .

Step-by-step explanation:

The difference quotient is a formula that computes the slope of the secant line through two points on the graph of <em>f</em>. These are the points with x-coordinates x and x + h. The difference quotient is used in the definition the derivative and it is given by

$\frac{f(x+h)-f(x)}{h}$

So, for the function $f(x)=3x^2$ the difference quotient is:

To find $f(x+h)$ , plug $x+h$ instead of $x$

$f\left(x+h\right)=3 \left(h + x\right)^{2}$

Finally,

$\frac{f\left(x+h\right)-f\left(x\right)}{h}=\frac{\left(3 \left(h + x\right)^{2}\right)-\left(3 x^{2}\right)}{h}$

$\frac{3\left(\left(h+x\right)^2-x^2\right)}{h} \\\\\frac{3(h^2+2hx+x^2-x^2)}{h} \\\\\frac{3h\left(h+2x\right)}{h}\\\\3h+6x$

The difference quotient for $f(x)=3x^2$ is $3 h + 6 x$ .

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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