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vampirchik [111]
3 years ago
12

4. The constant of proportionality between the height of the water in a sink (h) in centimeters and the number of minutes it has

been filling (m) is 0.95. The sink has been filling for 40 minutes. What is the height of the water in the sink?
Mathematics
1 answer:
RUDIKE [14]3 years ago
6 0

Answer:

i got 38

Step-by-step explanation:

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What is the LCM of 5 and 12
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60. The answer is 60
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In the triangle of ABC, D is a point on AB , AC = 7, AD = 6, and BC = 18. The length of DB could be
Ray Of Light [21]

Answer:

19 > DB > 5

Step-by-step explanation:

In a triangle Δ ABC, AC = 7, and BC = 18.

Therefore, the length of the third side of the triangle Δ ABC i.e. length of AB can have a maximum value of < (7 + 18) i.e. 25 and the minimum value of the length AB will be > (18 - 7) i.e. 11

Hence, the length of AB will be given by 25 > AB > 11.

Now, AB = AD + DB = 6 + DB {Since length of AD is given to be 6}

Therefore, 25 > 6 + DB > 11

⇒ 19 > DB > 5 (Answer)

8 0
3 years ago
The mean number of people per day visiting a museum in July was 120. If 20 more people each day visited the museum in August, wh
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The correct answer is 140 because the mean, average, number from July per day represents how many people would have visited each day if they were all even.

If there were 20 more people each day in August, the mean would be 140. This would represent how many people visited each day.
8 0
3 years ago
Read 2 more answers
Hello can u please help
Andrei [34K]

y = mx + b

-3 = -2(-5) + b

-3 = 10 + b

-13 = b

y = -2m - 13

The line would pass through -13 on the y-axis and it would go down 2 and move to the right 1 for every new point.

Hope this helps! ;)

6 0
3 years ago
Read 2 more answers
Question :-
DochEvi [55]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

5 0
2 years ago
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