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2 years ago

What is the common ratio of the associated geometric sequence?

1 answer:

4 0

Common Ratio. For a geometric sequence or geometric series, the common ratio is the ratio of a term to the previous term. This ratio is usually indicated by the variable r.

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Which is the BEST estimate of the quotient of 149 divided by 33?

Harman [31]

Answer:

Step-by-step explanation:

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2 years ago

1. A point on the ground is 50 feet from my house. The angle of elevation to the top of the house is 48 Find the height of the h

Georgia [21]

Answer:

(1)55.5 feet

(2)7.5 feet

Step-by-step explanation:

Question 1

The diagram is attached below.

Using Trigonometric ratio

$\tan 48^\circ = \dfrac{h}{50} \\h=50 \times \tan 48^\circ\\h=55.5$ feet (to the nearest tenth)$

The height of the house is 55.5 feet to the nearest tenth.

Question 2

In the diagram, we are required to find the distance the bird must fly to be directly above the fish. This has been represented by x.

Using Trigonometric ratio

$\tan 15^\circ = \dfrac{2}{x} \\x \tan 15^\circ=2\\x=2 \div \tan 15^\circ\\x=7.5 $ feet (to the nearest tenth)$

The distance the bird must fly to be directly above the fish is 7.5 feet.

6 0

3 years ago

A cookie recipe calls for 1/3 of a cup of sugar and 1 1/2 cups of flour. What is the unit rate of flour to sugar for the cookie

Serggg [28]

Answer:

Rate = 4.5

Step-by-step explanation:

It is given that,

A cookie recipe calls for 1/3 of a cup of sugar and 1 1/2 cups of flour.

We need to find the unit rate of flour to sugar for the cookie recipe. It can be calculated as follows :

$U=\dfrac{\text{No of cups of flour}}{\text{No of cups of sugar}}\\\\=\dfrac{1\dfrac{1}{2}}{\dfrac{1}{3}}\\\\=\dfrac{\dfrac{3}{2}}{\dfrac{1}{3}}\\\\=\dfrac{3}{2}\times 3\\\\=4.5$

So, the unit rate of flour to sugar for the cookie recipe is 4.5

6 0

2 years ago

A box is dragged 16 m across a level floor by a 25-N force at an angle of 45° to the floor. It is then dragged by

Nuetrik [128]

solution

W=f×d×cos theta

=25N×16m×cos 45°

=400Nm×cos 45°

=282.84J

W=f×d×cos theta

=25N×7m×cos 10°

=175Nm×cos10°

=172.34J

Total workdone=282.84J+172.34J=455.18J

7 0

2 years ago

Drawing Conclusions

maksim [4K]

Answer:

Some of the Exponents = -2 that is true, not 2.

Step-by-step explanation:

Let's check one at a time.

(a)The 6 without an exponent is equivalent to the 6 having a 0 exponent.

$6^{0} =1$ and $6^{1}$ = 6 (no exponent. 6 $\neq$ 1 therefore this statement is False.

(b)The sum of the exponents is -2.

let's check , if the base is same we can add the exponents that is the exponent rule.(well established).

if we add exponents in the given expression we get.

$6^{1} 6^{0} 6^{3} =6^{1+0+(-3)} =6^{-2}$ , therefore we can see that the sum of the exponents = -2 this is true.

(c) An equivalent expression is 65.6-7, lets evaluate our above expression, it is equal to $\frac{1}{36}$ which we can see that $\frac{1}{36} \neq 65.6-7$ ,therefore this statement is false as well.

3 0

2 years ago