Answer this please lol
2 answers:
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The average density of the rod is 0.704 kg/m.
For given question,
We have been given the linear density in a rod 5 m long is 10 / x + 4 kg/m, where x is measured in meters from one end of the rod.
We need to find the
The length of rod is, L = 5 m.
The linear density of rod is, ρ = 10/( x + 4) kg/m
To find the average density we need to integrate the linear density from x₁ = 0 to x₂ = 5,
The expression for the average density is given as,
⇒ ρ'
......................(1)
Using u = x + 4
du = dx
u₁ = x₁ + 4
u₁ = 0 + 4
u₁ = 4
and
u₂ = x₂ + 4
u₂ = 5 + 4
u₂ = 9
By entering the values above into (1), we have:
⇒ ρ'
= 0.704
Thus, we can conclude that the average density of the rod is 0.704 kg/m.
Learn more about the average density here:
#SPJ4
SOLUTION:
Case: Volume of Sphere
Method:
a) The volume of a sphere whose diameter, d= 28in
The radius,
r= 28/2
r= 14 in
The Volume, therefore:
b) When half of the volume is used,
c) The radius of the halved volume
Final answer: (To 2 d.p)
a) 11494.04 cubic inches
b) 5747.02 cubic inches
c) 11.11 inches