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3 years ago

Write the standard form of the equation of a circle with a radius of 2 and center at (4,-5)

Mathematics

2 answers:

Veronika [31]3 years ago

7 0

center-radius form of the circle (x – h)^2 + (y – k^)2 = r^2

(x-4)^2 + (y--5)^2 = 2^2

(x-4)^2 +(y+5)^2 = 4

yaroslaw [1]3 years ago

6 0

Answer:

$(x-4)^2+(y+5)^2=4$

Step-by-step explanation:

We are given a circle with a radius of 2 with a center at the point (4, -5).

Assuming x and y to be the coordinates of any point on the circle, we can find the equation of the circle by using the following distance formula:

$r=\sqrt{(x_1-x)^2+(y_1-y)^2}$

Putting the given values to get:

$2=\sqrt{(x-4)^2+(y+5)^2}$

Taking square on both sides to get:

$4=(x-4)^2+(y+5)^2$

Therefore, the equation of the given circle with radius 2 and center at (4, -5) is $(x-4)^2+(y+5)^2=4$ .

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