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2 years ago

What is the solution of the equation 3^5 sqrt (x+2)^3+3=27?

2 answers:

7 0

We rewrite the function:
(3 ^ 5) * (sqrt (x + 2) ^ 3 + 3) = 27
(3 ^ 5) * (sqrt (x + 2) ^ 3) = 27-3
(3 ^ 5) * (sqrt (x + 2) ^ 3) = 24
(3 ^ 4) * (sqrt (x + 2) ^ 3) = 8
((3 ^ 4) * (sqrt (x + 2) ^ 3)) ^ 2 = (8) ^ 2
(3 ^ 8) * (x + 2) ^ 3 = 64
((3 ^ 8) * (x + 2) ^ 3) ^ (1/3) = (64) ^ (1/3)
(3 ^ (8/3)) * (x + 2) = 4
(x + 2) = 4 * (3 ^ (3/8))
x = 4 * (3 ^ (3/8)) - 2
Answer:
the solution of the equation 3 ^ 5 sqrt (x + 2) ^ 3 + 3 = 27 is
x = 4 * (3 ^ (3/8)) - 2

BlackZzzverrR [31]2 years ago

4 0

3^5) (x + 2)^(3/2) + 3 = 27
(x + 2)^(3/2) = 24 / 243 
x + 2 = [ 24 / 243 ]^(2/3) 
x + 2 = [ 8 / 81 ]^(2/3) 
x = [ 4 / 81^(2/3) ] - 2 =-1.786

the answer is x=-1.786

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valentina_108 [34]

Answer:

60 minutes

Step-by-step explanation:

Let the number of minutes be represented as x

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Plan A charges $35 plus $0.25 per minute for calls.

$35 + $0.25 × x

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For Plan B

Plan B charges $20 plus $0.50 per minute for calls.

$20 + $0.50 × x

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For what number of minutes do both plans cost the same amount?

This is calculated by equating Plan A to Plan B

Plan A = Plan B

35 + 0.25x = 20 + 0.50x

Collect like terms

35 - 20 = 0.50x - 0.25x

15 = 0.25x

x = 15/0.25

x = 60 minutes.

Hence, the number of minutes that both plans cost the same amount is 60 minutes

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2 years ago

If the mass of a material is 44 grams and the volume of the material is 6 cm^3, what would the density of the material be?

Svetlanka [38]

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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1.) Find the value of the discriminant and the the number of real solutions of

ruslelena [56]

Hi there!

When we have an equation standard form...
$a {x}^{2} + bx + c = 0$
...the formula of the discriminant is
D = b^2 - 4ac

When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions

1.) Find the value of the discriminant and the the number of real solutions of
x^2-8x+7=0

Plug in the values from the equation into the formula of the discriminant

$( - 8) {}^{2} - 4 \times 1 \times 7 = 64 - 28 = 36$

D > 0 and therefore we have two real solutions.

2.) Find the value of the discriminant and the number of real solutions of
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Again, plug in the values from the equation into the formula of the discriminant.

${4}^{2} - 4 \times 2 \times 2 = 16 - 16 = 0$

D = 0 and therefore we have one real solution.

~ Hope this helps you.

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