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SVETLANKA909090 [29]
3 years ago
7

What is the solution of the equation 3^5 sqrt (x+2)^3+3=27?

Mathematics
2 answers:
borishaifa [10]3 years ago
7 0
We rewrite the function:
 (3 ^ 5) * (sqrt (x + 2) ^ 3 + 3) = 27
 (3 ^ 5) * (sqrt (x + 2) ^ 3) = 27-3
 (3 ^ 5) * (sqrt (x + 2) ^ 3) = 24
 (3 ^ 4) * (sqrt (x + 2) ^ 3) = 8
 ((3 ^ 4) * (sqrt (x + 2) ^ 3)) ^ 2 = (8) ^ 2
 (3 ^ 8) * (x + 2) ^ 3 = 64
 ((3 ^ 8) * (x + 2) ^ 3) ^ (1/3) = (64) ^ (1/3)
 (3 ^ (8/3)) * (x + 2) = 4
 (x + 2) = 4 * (3 ^ (3/8))
 x = 4 * (3 ^ (3/8)) - 2
 Answer:
 the solution of the equation 3 ^ 5 sqrt (x + 2) ^ 3 + 3 = 27 is
 x = 4 * (3 ^ (3/8)) - 2
BlackZzzverrR [31]3 years ago
4 0
3^5) (x + 2)^(3/2) + 3 = 27 
<span>(x + 2)^(3/2) = 24 / 243 </span>
<span>x + 2 = [ 24 / 243 ]^(2/3) </span>
<span>x + 2 = [ 8 / 81 ]^(2/3) </span>
<span>x = [ 4 / 81^(2/3) ] - 2 =-1.786

the answer is x=-1.786</span>
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