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3 years ago

What is the solution of the equation 3^5 sqrt (x+2)^3+3=27?

2 answers:

7 0

We rewrite the function:
(3 ^ 5) * (sqrt (x + 2) ^ 3 + 3) = 27
(3 ^ 5) * (sqrt (x + 2) ^ 3) = 27-3
(3 ^ 5) * (sqrt (x + 2) ^ 3) = 24
(3 ^ 4) * (sqrt (x + 2) ^ 3) = 8
((3 ^ 4) * (sqrt (x + 2) ^ 3)) ^ 2 = (8) ^ 2
(3 ^ 8) * (x + 2) ^ 3 = 64
((3 ^ 8) * (x + 2) ^ 3) ^ (1/3) = (64) ^ (1/3)
(3 ^ (8/3)) * (x + 2) = 4
(x + 2) = 4 * (3 ^ (3/8))
x = 4 * (3 ^ (3/8)) - 2
Answer:
the solution of the equation 3 ^ 5 sqrt (x + 2) ^ 3 + 3 = 27 is
x = 4 * (3 ^ (3/8)) - 2

BlackZzzverrR [31]3 years ago

4 0

3^5) (x + 2)^(3/2) + 3 = 27
(x + 2)^(3/2) = 24 / 243 
x + 2 = [ 24 / 243 ]^(2/3) 
x + 2 = [ 8 / 81 ]^(2/3) 
x = [ 4 / 81^(2/3) ] - 2 =-1.786

the answer is x=-1.786

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