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3 years ago

15

Help pls ill give briniest

1 answer:

Tems11 [23]3 years ago

5 0

Answer:

4. a) kilometer

b) liter

5. a) gram

b) meter

I'm not totally sure if I'm right

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Neporo4naja [7]

So, when we're tasked with things like this, rewriting everything in terms of sine and cosine and combining fractions often trivializes things, so doing just that gives us:

$\frac{\frac{1}{\cos{x}}-\frac{1}{\sin{x}}}{\frac{\cos{x}}{\sin{x}}-1}= \\\frac{\frac{=(\cos{x}-\sin{x})}{\cos{x}\sin{x}}}{\frac{\cos{x}}{\sin{x}}-\frac{\sin{x}}{\sin{x}}}=\\\frac{-(\cos{x}-\sin{x})}{\cos{x}\sin{x}}*\frac{\sin{x}}{\cos{x}-\sin{x}}=\\-\frac{1}{\cos{x}}$

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3 years ago

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fgiga [73]

Answer:

The length of side of largest square is 15 inches

Step-by-step explanation:

The given suares are when joined in the way as shown in picture their sides form a right agnled triangle.

Area of square 1 and perimeter of square 2 will be used to calculate the sides of the triangle.

So,

<u>Area of square 1: 81 square inches</u>

$s^2 = A\\s^2 = 81\\\sqrt{s^2} = \sqrt{81}\\s = 9$

<u>Perimeter of square 2: 48 inches</u>

$4*side = P\\4* side = 48\\side = \frac{48}{4}\\side = 12\ inches$

We can see that a right angled triangle is formed.

Here

Base = 12 inches

Perpendicular = 9 inches

And the side of largest square will be hypotenuse.

Pythagoras theorem can be used to find the length.

$(H)^2 = (P)^2+(B)^2\\H^2 = (9)^2+(12)^2\\H^2 = 81+144\\H^2 = 225\\\sqrt{H^2} = \sqrt{225}\\H = 15$

Hence,

The length of side of largest square is 15 inches

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3 years ago

What is part of a line, has one endpoint, and continues in one direction

Lina20 [59]

The answer is a ray.

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