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lesya692 [45]
3 years ago
12

I need help. Find the value of x

Mathematics
2 answers:
arlik [135]3 years ago
5 0

Answer:

x = 6

Step-by-step explanation:

In triangle ABC, BD is the bisector of angle ABD.

Therefore by angle bisector property:

\frac{x}{8}  =  \frac{3}{4}  \\ x =  \frac{8 \times 3}{4}  \\ x = 2 \times 3 \\ \huge \red{ \boxed{ x = 6}}

Tanzania [10]3 years ago
4 0

Answer:

8

Step-by-step explanation:

it's 8 because the sides facing each other equal

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Is a relation always a function? Is a function always a relation? Explain.
katen-ka-za [31]

A function is always a relation but relation is not always a function

<u>Solution:</u>

Given that, we have to explain Is a relation always a function and is a function always a relation

Note that both functions and relations are defined as sets of lists.  

In fact, every function is a relation. However, not every relation is a function.  A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y.

That is, given an element x in X, there is only one element in Y that x is related to.

For example, consider the following sets X and Y. Let me give you a relation between them that is not a function;

X = { 1, 2, 3 }

Y = { a , b , c, d }

Relation from X to Y : { (1,a) , (2, b) , (2, c) , (3, d) }

This relation is not a function from X to Y because the element 2 in X is related to two different elements, b and c

Relation from X to Y that is a function: { (1,d) , (2,d) , (3, a) }

This is a function since each element from X is related to only one element in Y. Note that it is okay for two different elements in X to be related to the same element in Y. It's still a function, it's just not a one-to-one function.

So, we can say that function is a type of relation.

Which means whatever a function occurs, it will be a relation from one set to other.

But when a relation occurs it may be a function but need not be always a function.

Hence, a function is always a relation but relation is not always a function.

8 0
3 years ago
Plz help me. will give brainliest!!
Nesterboy [21]

Answer:

1. 110

2. 84

Step-by-step explanation:

6 0
3 years ago
how many solutions does the equation 2(2x- 10)-8 =-2(14-3x) have?A.exactly one solution B. exactly two solutions C. no solution
Zarrin [17]

Answer: it has no solutions

Step-by-step explanation:

Factor then solve to find the complex solutions.

5 0
2 years ago
Enter your answer and show all the steps that you use to solve this problem in the space provided.
rodikova [14]

Answer:

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

Step-by-step explanation:

f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4

Step 1. Calculate the difference between the functions

(a) Write the two functions, one above the other, in decreasing order of exponents.

ƒ(x) = 9x³ + 2x² - 5x + 4

g(x) = 5x³           - 7x + 4

(b) Create a subtraction problem using the two functions

        ƒ(x) =    9x³ + 2x² - 5x + 4

      -g(x) =  <u>-(5x³           - 7x + 4) </u>

ƒ(x) -g(x)=

(c). Subtract terms with the same exponent of x

        ƒ(x)   =    9x³ + 2x² - 5x + 4

      -g(x)  =   <u>-(5x³          -  7x + 4) </u>

ƒ(x) -g(x) =      4x³ + 2x² + 2x

Step 2. Factor the expression

y = 4x³ + 2x² + 2x

Factor 2x from each term

y = 2x(2x² + x + 1)

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

5 0
3 years ago
Find the distance between the pair of points.
SVEN [57.7K]

Answer:

Distance is \sqrt{290} units

Step-by-step explanation:

Use the distance formula which is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where d is the distance between points (x_1,y_1) and (x_2,y_2)

We are given that (x_1,y_1) is (-6,-23) and (x_2,y_2) is (-23,-24), therefore the distance between the two points is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(-23-(-6))^2+(-24-(-23))^2}

d=\sqrt{(-23+6))^2+(-24+23))^2}

d=\sqrt{(-17)^2+(-1)^2}

d=\sqrt{289+1}

d=\sqrt{290}

Therefore, the distance between (-6,-23) and (-23,-24) is \sqrt{290} units.

3 0
2 years ago
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