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Tom [10]
3 years ago
12

The margin requirement on a stock purchase is 25%. you fully use the margin allowed to purchase 100 shares of msft at $25. if th

e price drops to $22, what is your percentage loss?
Mathematics
1 answer:
Westkost [7]3 years ago
6 0
Thank you for posting your question here at brainly. I hope the answer will help you. Below is the solution:

Loss = (22-25)100 = -300
Amount invested = (.25 x 25) * 100 = 625
<span>Return = -300/625 = </span><span>-48%</span>
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7. Saturday night, Larry is attending the concert of his favorite rock band. Tickets were $250 plus 6% tax. Parking is $20 for t
ElenaW [278]

Answer:

$347.45

Step-by-step explanation:

total = tickets + parking + t shirt + meal

tickets = 250 + 6% tax

6% tax is of 250, so this is equal to

250 + 6% of 250

6% = 0.06 because we divide by 100 to convert to a decimal from a percentage

thus, tickets = 250 + 0.06 of 250 = 250 * 1 + 0.06 * 250 + 1.06 * 250 = 265

parking = 20

use a similar strategy from the tickets and apply that to the t shirt

t shirt = 35 + 7 % tax = 35 + 0.07 * 35 = 1.07 * 35 = 37.45

meal = 25

total = 265 + 20 + 37.45 + 25 = $347.45

6 0
3 years ago
GEOMETRY HELP PLEASE!! 20 points
Ghella [55]

Answer:

This calculator is helpful for deciding how many tablets/capsuwhy

6 0
2 years ago
PLS HELP ASAP
daser333 [38]

Answer:

-3/4 ÷ 2/-8 = 3 ( i think so! )

4 0
3 years ago
Read 2 more answers
The table shows the viscosity of an oil as a function of temperature. Identify a quadratic model for the viscosity, given the te
777dan777 [17]

Answer:

The viscosity at 140°C is predicted to be 7.2

Step-by-step explanation:

The function that model the relationship between viscosity and temperature = Quadratic model

The general form of a quadratic equation is y = a·x² + b·x + c

Therefore, we have;

When y = 10.8, x = 110, which gives;

10.8 = a·110² + b·110 + c = 12100·a + 110·b + c

10.8 = 12100·a + 110·b + c

When y =8.2, x = 130

8.2 = a· 130² + b· 130 + c = 16900·a + 130·b + c

8.2 = 16900·a + 130·b + c

When y = 160, x = 5.8

5.8 = a·160² + b·160 + c = 25600·a + 160·b + c

5.8 = 25600·a + 160·b + c

The three equations above can be listed as follows;

10.8 = 12100·a + 110·b + c

8.2 = 16900·a + 130·b + c

5.8 = 25600·a + 160·b + c

Solving using matrices gives;

\begin{bmatrix}12100 & 110 & 1\\ 16900 & 130 & 1\\ 25600 & 160 & 1\end{bmatrix} \begin{bmatrix}a\\ b\\ c\end{bmatrix} = \begin{bmatrix}10.8\\ 8.2\\ 5.8\end{bmatrix}

\begin{bmatrix}a\\ b\\ c\end{bmatrix} = -\dfrac{1}{3000}\begin{bmatrix}3 & -5 & 2\\ -867 & 1350 & -480\\ 62400 & -88000 & 28600\end{vmatrix} \begin{bmatrix}10.8\\ 8.2\\ 5.8\end{bmatrix}

From which we have;

a = 0.001, b = -0.37, c = 39.4

Substituting gives;

y = 0.001·x² - 0.37·x + 39.4

When x = 140

y = 0.962·140² - 0.37·140 + 39.4= 7.2

The viscosity at 140°C = 7.2.

8 0
3 years ago
Please help. im lost. Question is in the picture
navik [9.2K]

In triangle QRT and triangle RTS , we have;
1.QR =SR (given)
2.RT bisects QS at T ( given )
3.T is the midpoint of QS (since RT is the bisector of QS i.e. QT=TS)
4.QT=TS (mid Point theorem)
5.TR=TR (common side)
6.triangle QRT congruent to triangle RTS (SAS criterion rule)
Hope this helps u....!!!

6 0
3 years ago
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