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4 years ago

tabita bought peppers that cost 0.79 per pound she paid 3.95 for the peppers how many pounds did she buy

Mathematics

1 answer:

Akimi4 [234]4 years ago

6 0

5 pounds because 3.95/0.79 =5

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#2 & #3 with answer and explanation please??????

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2) If we have 2 points K & M with their coordinates (x₁,y₁) & (x₂,y₂), the the distance of KM is given by the formula:

KM = √[(x₂-x₁)² + (y₂-y1)²] ; K(2,3) & M(5,1) (Given)
KM = √[(5-2)² + (1-3)²] ==>√(9+ 4) ==> KM = √13 (ANSWER D)

3) The coordinates are A(4,7) & B(-3,9). Follow & apply the same methodology as above:

AB =√[(x₂-x₁)² + (y₂-y1)²] ; A(4,7) & B(-3,9) (Given)

AB =√[(-3-4)² + (9-7)²] ==> AB = √[(-7)² + (2)²] ==> √(49+4) =√53 (B)

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3 years ago

the interval [2, 4] is divided into n equal subintervals of length delta x. What is delta x (in terms of k and n)

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Each subinterval would have length ∆x = (4 - 2)/n = 2/n

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2 years ago

Round 7,248,193,675 to the nearest billion

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7 billion is the answer.

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4 years ago

A motorboat traveling with a current can go 120 km in 4 hours. Against the current, it takes 6 hours to go the same distance. Fi

charle [14.2K]

The speed of motorboat in still water is 25 km/hr and speed of current is 5 km/hr

Solution:

Given that, motorboat traveling with a current can go 120 km in 4 hours

In water, the direction along the stream is called downstream

Let us find the downstream speed

Downstream distance = 120 km

time taken in downstream = 4 hours

The speed is given by formula:

$speed = \frac{distance}{time}$

$\text{ Downstream speed } = \frac{120}{4} = 30$

Thus downstream speed = 30 kilometer per hour

Against the current, it takes 6 hours to go the same distance

The direction against the stream is called upstream

Let us find upstream speed

Upstream distance = 120 km

time taken in upstream = 6 hours

$\text{Upstream speed } = \frac{120}{6} = 20$

Thus upstream speed is 20 kilometer per hour

Formula to use:

If the speed downstream is a km/hr and the speed upstream is b km/hr, then:

$\text{Speed in still water } = \frac{1}{2}(a+b) \text{ kilometer per hour }\\\\\text{Speed of stream } = \frac{1}{2}(a-b) \text{ kilometer per hour }$

Therefore,

$\text{Speed of boat in still water } = \frac{1}{2}(30+20) = 25\\\\\text{Speed of stream } = \frac{1}{2}(30-20) = 5$

Thus speed of motorboat in still water is 25 km/hr and speed of current is 5 km/hr

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4 years ago

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