Answer:
the answer is A. 10/8 cubic in.
Step-by-step explanation:
V = LWH
length is 2 (1/3 in)
width is 3 (1/3 in)
height is 5 (1/3 in)
V = 2/3 in * 3/3 in * 5/3 in.
V = 10/9 cubic in.
Answer: a = 294 square inches
Use the formula: A = 6a^2
I=k/d^2
4=k/d^2 and 1=k/64 so if we divide the first by the second we get:
4/1=(k/d^2)/(k/64)
4=(k/d^2)*(64/k)
4=64/d^2
d^2=64/4
d^2=16
d=4 meters
The height of the triangle is 48/b or 48 over b. That's all I can tell you with the information given.
In your question where ask to find the Standard Normal Distribution of the following:
give probabilities for 0<Z<infinity.
For these ranges, you can read directly, for example,
P(Z<1.96)=0.975.
So for #1, you read directly on the line 1.3 and column 0.03.
For #2, we note that the distribution is symmetrical about Z=0, so
P(Z<-2.33) is the same as P(Z>2.33)
which again is the same as
1-P(Z<2.33) because we know that the area under a probability distribution function adds up to 1.
For the remaining questions, work is similar to #2.