Answer:
It's heavy cream
Step-by-step explanation:
Homogenized milk has a density of 1.032 kg/L and
heavy cream has a density of 1.005 kg/L at 10°C.
At 10°C, a container holding 8 liters of liquid weighs 8.04 kilograms
To determine which container hold homogenized milk or heavy cream and How I know?
We findo the density of the measurements given and whatever it correspond to is what it is
First mass is 8.04kg
Liquid contained is 8 litres
SInce the density is kg/L
No need for conversion
Density = mass/volume = 8.04/8= 1.005kg/L
Heavy cream has a density of 1.005 kg/L at 10°C.
Therefore it correspond
4 500-60 = 4 440
4 440/38 = 116.8
At most they would be able to invite 116 people to the reception with their budget.
Could you give Brainliest please???
Answer:
y = 2 - 1/2x
Step-by-step explanation:
So we are given the equation 3x + 6y = 12 and are ask to find y.
To find y you must isolate it first.
3x + 6y = 12
(Subtract 3x to isolate the y term)
6y = 12 - 3x
(Divide both sides by 6 to isolate the variable)
y = 2 - 3/6x
(Simplify)
y = 2 - 1/2x
And that is your answer since there is a second variable.
