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2 years ago

Please help!!!!!!!!!! im struggling

Mathematics

2 answers:

Elenna [48]2 years ago

8 0

Answer:

Step-by-step explanation:

If you look at how many lines are lines up at the ten that is the answer

DochEvi [55]2 years ago

4 0

Answer:

Step-by-step explanation:

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LiRa [457]

I think this is right

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3 years ago

Read 2 more answers

What is the sum of an infinite geometric series if the first term is 81 and the common ratio is 2⁄3?

Marrrta [24]

the sum to infinity of a geometric series = $\frac{a}{1-r}$

where a is the first term and r the common ratio

= $\frac{81}{\frac{1}{3} }$ = 81 × 3 = 243

4 0

3 years ago

The left and right page numbers on an

liubo4ka [24]

The pages would be 166 and 167

7 0

3 years ago

Ill mark brainiest please help me!!!!!!!!

IgorC [24]

Answer:

yes , 33^2 + 56^2 = 65^2 and obtuse

Step-by-step explanation:

<h2>Question 3</h2>

make use of the Pythagoras theorem

which is :

c^2 = a^2 + b^2

where c is the hypotenuse.

now put the values in the equation

65^2 = 56^2 + 33 ^2

the answer is :

yes , 33^2 + 56^2 = 65^2

<h2>Question 4</h2>

note if :

c^2 = a^2 + b^2 ----------- right

c^2 < a^2 + b^2------------ acute

c^2 > a^2 + b^2------------- obtuse

hence :

16 + 30 > 38

therefore its : obtuse

4 0

3 years ago

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let $p_1$ = percentage of employed workers who have registered to vote.

$p_2$ = percentage of unemployed workers who have registered to vote.

So, Null Hypothesis, $H_0$ : $p_1\leq p_2$ {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, $H_A$ : $p_1>p_2$ {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of employed workers who have registered to vote = $\frac{287}{513}$ = 0.56

$\hat p_2$ = sample proportion of unemployed workers who have registered to vote = $\frac{280}{604}$ = 0.46

$n_1$ = sample of employed persons = 513

$n_2$ = sample of unemployed persons = 604

So, the test statistics = $\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }$

= 3.349

The value of z test statistics is 3.349.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0

3 years ago