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3 years ago

How can you dived 678968/78= what

Mathematics

1 answer:

9966 [12]3 years ago

6 0

Answer:

8,704.717948718

Step-by-step explanation:

678,968 divided by 78 is 8,704.717948718

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I don't get this one too can someone explain it please

lukranit [14]

Answer:

15ab

Step-by-step explanation:

When you multiply out the square (p+q)^2, you get the trinomial ...

(p +q)^2 = p^2 + 2pq + q^2

Your binomial is (3a+2.5b), so you have ...

p = 3a

q = 2.5b

and the trinomial you get when you multiply it out is ...

(3a)^2 + 2(3a)(2.5b) + (2.5b)^2

= 9a^2 + 15ab + 6.25b^2

The first and last of these terms are shown on the right side of the given expression, so to finish out the identity, you need to replace * with 15ab.

5 0

3 years ago

Hector recorded the amount of time he spent running for 3 days what is the total number of hours hector spent running

lozanna [386]

Well you have to go by 24x3 and that equals 72 miles

5 0

3 years ago

Read 2 more answers

Which best describes the figure that is represented by the following coordinates

AveGali [126]

Answer: Rectangle
Reasoning: 4 straight sides, 2 pairs of sides of equal length.

8 0

3 years ago

Read 2 more answers

Change 22 metres per second to a speed in kilometres per hour. Show your working clearly.

masha68 [24]

Answer:

79.2 km/hour

Step-by-step explanation:

1 m/sec= 3.6 km/hour 22m/sec= ? so just multiply 22 m/sec by 3.6 km/hour then the answer will be :- 79.2 km/hour

7 0

3 years ago

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

3 years ago