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Gekata [30.6K]
3 years ago
9

when the cost of a car was was $8, there were 90 customers. when the cost was reduced to $4, there were 170 costomers. assume th

e relationship is linear. what is the slope of the line
Mathematics
1 answer:
Olegator [25]3 years ago
8 0
Write each set as an ordered pair then use the slope formula. As the number of people go up the cost goes down so you know the slope will be negative. -20 (170-90)/(4-8)
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What number is 95% of 350
Roman55 [17]
So, we have the unknown value, let's call it "x".
95% is .95 as a decimal.
So, let's find what .95*350 is.
.95*350=332.5
So, the unknown value is 332.5.
332.5 is 95% of 350.
4 0
3 years ago
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What is the measure of angle BXF?​
tamaranim1 [39]

Answer:

BXF = 75

Step-by-step explanation:

We know that CXE is a straight line

A straight line is 180 degrees

CXE = CXG + GXD +DXE

Substituting what we know

180 = 85+ GXD + 20

Combine like terms

180 = 105+GXD

Subtract 105 from each side

180-105 = 105-105 +GXD

75 = GXD

GXD and BXF  are vertical angles

GXD = 75 which means BXF = 75

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3 years ago
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Convert each improper fraction to a mixed number<br> 5/3=<br> 17/6=<br> 16/5=<br> 9/4=<br> 7/2=
AlexFokin [52]

5/3=1 2/3

17/6=2 5/6

16/5=3 1/5

9/4=2 1/4

7/2=3 1/2

Hope this helps!

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Find the direction cosines and direction angles of the vector. (Give the direction angles correct to the nearest degree.) 5, 1,
Dahasolnce [82]

Answer:

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

Step-by-step explanation:

For a given vector a = ai + aj + ak, its direction cosines are the cosines of the angles which it makes with the x, y and z axes.

If a makes angles α, β, and γ (which are the direction angles) with the x, y and z axes respectively, then its direction cosines are: cos α, cos β and cos γ in the x, y and z axes respectively.

Where;

cos α = \frac{a . i}{|a| . |i|}               ---------------------(i)

cos β = \frac{a.j}{|a||j|}               ---------------------(ii)

cos γ = \frac{a.k}{|a|.|k|}             ----------------------(iii)

<em>And from these we can get the direction angles as follows;</em>

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

Now to the question:

Let the given vector be

a = 5i + j + 4k

a . i =  (5i + j + 4k) . (i)

a . i = 5         [a.i <em>is just the x component of the vector</em>]

a . j = 1            [<em>the y component of the vector</em>]

a . k = 4          [<em>the z component of the vector</em>]

<em>Also</em>

|a|. |i| = |a|. |j| = |a|. |k| = |a|           [since |i| = |j| = |k| = 1]

|a| = \sqrt{5^2 + 1^2 + 4^2}

|a| = \sqrt{25 + 1 + 16}

|a| = \sqrt{42}

Now substitute these values into equations (i) - (iii) to get the direction cosines. i.e

cos α = \frac{5}{\sqrt{42} }

cos β =  \frac{1}{\sqrt{42} }              

cos γ =  \frac{4}{\sqrt{42} }

From the value, now find the direction angles as follows;

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

α =  cos⁻¹ ( \frac{5}{\sqrt{42} } )

α =  cos⁻¹ (\frac{5}{6.481} )

α =  cos⁻¹ (0.7715)

α = 39.51

α = 40°

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

β = cos⁻¹ ( \frac{1}{\sqrt{42} } )

β = cos⁻¹ ( \frac{1}{6.481 } )

β = cos⁻¹ ( 0.1543 )

β = 81.12

β = 81°

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

γ = cos⁻¹ (\frac{4}{\sqrt{42} })

γ = cos⁻¹ (\frac{4}{6.481})

γ = cos⁻¹ (0.6172)

γ = 51.89

γ = 52°

<u>Conclusion:</u>

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

3 0
3 years ago
Determine the slope of the line that passes through the points (-4, 6) and (0, 4).
Dennis_Churaev [7]
Slope = rise/run = (change in y)/(change in x)
Slope = (4-6)/(0-(-4)) = (-2)/(4)
Slope = -1/2 = -0.5
3 0
3 years ago
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