The LCD = 6x^2y^3 ( because LCD of 3 and 6 = 6, LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)
now divide 3x^2y into the LCD then multiply this by 5 to get the first term in the numerator and do similar process to get second term, so we get:-
5(2y^2) - 4(x)
------------------
6x^2y^3
= 2( 5y^2 - 2x)
-----------------
6x^2y^3
= 5y^2 - 2x
-----------
3x^2y^3
Answer:-4y^3-12y^2-7x
Step-by-step explanation:if you collect the liked terms it will add up to get that
Answer:
AE = 18 units
Step-by-step explanation:
Δ AEB and Δ DEC are similar , then corresponding sides are in proportion, that is
=
, substitute values
=
( cross- multiply )
10(2x + 4) = 12(x + 8) ← distribute parenthesis on both sides
20x + 40 = 12x + 96 ( subtract 12x from both sides )
8x + 40 = 96 ( subtract 40 from both sides )
8x = 56 ( divide both sides by 8 )
x = 7
Then
AE = 2x + 4 = 2(7) + 4 = 14 + 4 = 18 units
The approximate length of line segment XY is 20.8 units
<h3>
How to calculate the distance between two points</h3>
The formula for calculating the distance between two points is expressed as:
A = √(x2-x1)²+(y2-y1)²
Given the coordinate points X(–12, –6) and Y(5, 6). The distance between them is expressed as;
XY = √(5+12)²+(6+6)²
XY = √(17)²+(12)²
XY = √269 + 144
XY = 20.8
Hence the approximate length of line segment XY is 20.8 units
Learn more on distance formula here; brainly.com/question/661229
Answer:
x - 8y = - 56
Step-by-step explanation:
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
Given
y =
x + 7
Multiply through by 8 to clear the fraction
8y = x + 56 ( subtract 8y from both sides )
0 = x - 8y + 56 ( subtract 56 from both sides )
- 56 = x - 8y, that is
x - 8y = - 56 ← in standard form