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3 years ago

Write the equation of the line through each point.

Mathematics

1 answer:

Leya [2.2K]3 years ago

5 0

Answer:

The equation would be y = -1/3x + 4

Step-by-step explanation:

The first step to finding this equation needs to be solving the first equation for y so that we can find the slope.

-3x + y = 1

y = 3x + 1

Now that we have the slope of 3, we know the slope of a perpendicular line would be -1/3. This is because perpendicular lines have opposite and reciprocal slopes. We can then use this and the point to solve in point-slope form.

y - y1 = m(x - x1)

y - 2 = -1/3(x - 6)

y - 2 = -1/3x + 2

y = -1/3x + 4

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Step-by-step explanation:

$26.30 + $21.40= 47.07

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

What are the square number factors of 56?

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Answer:

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2 years ago

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4 years ago

An equation of the perpendicular bisector of the line segment with end points (3,0) and (-3,0) is

Norma-Jean [14]

Answer:

$x = 0$

Step-by-step explanation:

Given

$(x_1,y_1) = (3,0)$

$(x_2,y_2) = (-3,0)$

Required

The equation of the perpendicular bisector.

First, calculate the midpoint of the given endpoints

$(x,y) = 0.5(x_1 + x_2, y_1 + y_2)$

$(x,y) = 0.5(3-3, 0+ 0)$

$(x,y) = 0.5(0, 0)$

Open bracket

$(x,y) = (0.5*0, 0.5*0)$

$(x,y) = (0, 0)$

Next, determine the slope of the given endpoints.

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{0 - 0}{-3- 3}$

$m = \frac{0}{-6}$

$m = 0$

Next, calculate the slope of the perpendicular bisector.

When two lines are perpendicular, the relationship between them is:

$m_2 = -\frac{1}{m_1}$

In this case:

$m = m_1 = 0$

So:

$m_2 = -\frac{1}{0}$

$m_2 = unde\ fined$

Since the slope is $unde\ fined$ , the equation is:

$x = a$

Where:

$(x,y) = (a,b)$

Recall that:

$(x,y) = (0, 0)$

So:

$a = 0$

Hence, the equation is:

$x = 0$

5 0

3 years ago