$log_{2}x -log_{4}x= -2 \\ \\ log_{2}x -\frac{log_{2}x}{log_{2}4}= -2 \\ \\ log_{2}x*(1-\frac{1}{log_{2}4})=-2 \\ \\ log_{2}x*(1-\frac{1}{2})=-2 \\ \\\frac{1}{2}*log_{2}x=-2 \\ \\ log_{2}x=-4, \\ \\ x=2^{-4} = \frac{1}{2^{4}}=0.0625$

5 0

3 years ago

The line y = 5x/3 + b goes through the point (7, –1). What is the value of b?

mars1129 [50]

Answer:

$y=\frac{5}{3} x-\frac{38}{3}$

the value of b is -38/3

Step-by-step explanation:

$y=\frac{5}{3} x+b$ goes through the point (7,-1)

we need to find out b for the given equation using (7,-1)

Plug in 7 for x and -1 for y

$y=\frac{5}{3} x+b$

$-1=\frac{5}{3} (7)+b$

$-1=\frac{35}{3}+b$

subtract 35/3 from both sides

$-1 -\frac{35}{3} =b$

$\frac{-38}{3} =b$

Replace it in the original equation

$y=\frac{5}{3} x-\frac{38}{3}$

3 0

3 years ago