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ra1l [238]
3 years ago
10

I need help so bad I’m on the test right now I will mark Brainliest

Mathematics
2 answers:
wariber [46]3 years ago
7 0

Answer:

Step-by-step explanation:

\frac{3}{4} -4x+\frac{1}{2} x-\frac{1}{2} +\frac{1}{2} x\\=\frac{3}{4} -\frac{1}{2}-4 x+\frac{1}{2}x+\frac{1}{2} x\\=\frac{3-2}{4} -4x+\frac{1+1}{2} x\\=\frac{1}{4} -4x+\frac{2}{2} x\\=\frac{1}{4} -3x

Tatiana [17]3 years ago
4 0

Answer:

there u go

Step-by-step explanation:

Hope It helps u ....

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First lets start with number six. The only way to solve this is if you determine what "a" and "b" are using the first log they have given to you. log_a_ba=\frac{1}{3}

The first variable that I solved for was "a" and a=e^\frac{in(b)}{2}[tex]{[tex]  0}

The same is also true for "b", but when you put both "a" and "b" together the only combination that I have found to work is a=\frac{1}{2} , b=\frac{1}{4}

Next you plug these numbers in for "a" and "b" on the second equation to get something that looks like this: log_\frac{1}{2}_*_\frac{1}{4} (\frac{\sqrt{\frac{1}{2}}}{\sqrt[3]{\frac{1}{4}}}  )= -\frac{1}{18} and the picture below shows where the answer becomes a negative fraction.

https://www.symbolab.com/solver/logarithms-calculator/%20%5Clog_%7B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%5Cfrac%7B1%7D%7B4%7D%7D%5Cleft(%5Cfrac%7B%5Csqrt%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5Cright)

If you paste that link in your search bar it will give you a even more in depth understanding of how to get this answer

Next is #7, the easier of the two.There are two ways to solve for your answers. According to the graph of this equation there are four possible real solutions. x=2,-2,\sqrt{2}, and -\sqrt{2} . (This does not account for any complex solutions)

Notice that the bases are conjugates which is why the answers are so "nice"

The key is in the exponents

if x^{2} -3 =1 then the sum on the conjugates will be 10 so

x^{2}-3=1
x^{2}=4
so x= 2 or -2

Now for the other two

the solution is also true if x^{2}-3=-1

so

x^{2}-3 = -1\\x^{2}=2\\x=\left \{ {{\sqrt{2}} \atop {-\sqrt{2}}} \right.

the four real solutions are 2, -2, \sqrt{2} ,-\sqrt{2}



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Answer:

Step-by-step explanation:

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