
Collecting like terms,

Since the signs change when its position changes.

You can do 2 1/2 minus 1 1/8 to get 1 3/8. Your welcome and I hope you get a good grade
Answer:
27.9 i think in in a fraction 12 / 43
Step-by-step explanation:
Answer:
its answer 1.
Step-by-step explanation:
please mark me brainliest thank you for your time and have a nice rest of your day :)
Since

, we know that

follows a Poisson distribution with parameter

.
Now assuming

denote the mean and standard deviation of

, respectively, then we know right away that

and

.
So,