How do I write these ratios 10/20 and 2/2 in y=kx form

System of Equations <br> Need help<br> Trig

Yanka [14]

Looks like the system is

$\begin{cases}-2x+y+6z=1\\3x+2y+5z=16\\7x+3y-4z=11\end{cases}$

We can eliminate $y$ by taking

$(3x+2y+5z)-2(-2x+y+6z)=16-2(1)$

$\implies3x+2y+5z+4x-2y-12z=16-2$

$\implies7x-7z=14$

$\implies x-z=2$

so that $z=x-2$ , and

$(7x+3y-4z)-3(-2x+y+6z)=11-3(1)$

$\implies7x+3y-4z+6x-3y-18z=11-3$

$\implies13x-22z=8$

Substitute $z=x-2$ into this last equation and solve for $x$ :

$13x-22(x-2)=8$

$\implies13x-22x+44=8$

$\implies-9x=-36$

$\implies x=4$

Then

$z=x-2$

$\implies z=4-2$

$\implies z=2$

Plug these values into any one of the original equation to solve for $y$ :

$-2x+y+6z=1$

$\implies-2(4)+y+6(2)=1$

$\implies-8+y+12=1$

$\implies y=-3$

Hence the solution is x = 4, y = -3, and z = 2.

6 0

3 years ago

A group of students and workers entering a metro station were asked whether they were riding the bus or the subway. The two-way

BaLLatris [955]

Because this is a two-way table, the answer would be that 166 people were polled in total. Why? Well, there are lots of corresponding patterns leading up to this answer. We can easily find the answer by looking at the problem two different ways:

1st way: Identifying the missing solution by rows.

27 + 21 = 48 and 42 + 76 = 118, so we can find the missing value by adding 69 and 97 to get 166.

2nd way: Identifying the missing solution by columns.

27 + 42 = 69 and 21 + 76 = 97, so we can find the missing value by adding 48 and 118 to get 166, our missing solution.

Your final answer: 166 people were polled. Your answer would be D. If you need to better understand this, let me know and I will gladly assist you.

4 0

2 years ago

Read 2 more answers

(2 - 1 1/3) X 3/4<br> full answer pls

mihalych1998 [28]

12 83 cicnejwdhwigi3giu2

6 0

3 years ago

Read 2 more answers

The desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5

Alexeev081 [22]

Answer:

The null and alternative hypothesis are:

$H_0: \mu=5.5\\\\H_a:\mu< 5.5$

At a significance level of 0.05, there is enough evidence to support the claim that the population percentage of SiO2 is signficantly different from 5.5%.

P-value = 0.000004.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population percentage of SiO2 is signficantly different from 5.5%.

Then, the null and alternative hypothesis are:

$H_0: \mu=5.5\\\\H_a:\mu< 5.5$

The significance level is 0.05.

The sample has a size n=16.

The sample mean is M=5.21.

The standard deviation of the population is known and has a value of σ=0.26.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{0.26}{\sqrt{16}}=0.065$

Then, we can calculate the z-statistic as:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{5.21-5.5}{0.065}=\dfrac{-0.29}{0.065}=-4.462$

This test is a left-tailed test, so the P-value for this test is calculated as:

$\text{P-value}=P(z$

As the P-value (0.000004) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that the population percentage of SiO2 is signficantly different from 5.5%.

3 0

3 years ago

Please answer the problem with the correct answer and I will mark you brainliest and rate you five stars

nasty-shy [4]

Answer:

8

Step-by-step explanation:

The length of one side must be less than the length of the other two sides combined.

3 0

2 years ago