As you said, it could be anything, and there is proof that could be anything, which I'm sure your teacher would appreciate (writing proofs is a level of mathematical achievement that only hardcore math nerds can do, and it'd be super cool if you could write one yourself) A proof is basically a written mathematical description of exactly why something is the way it is.

But if you want to choose just one answer, I'd choose either 0 or undefined. If the answer is something that's bubbled in, then choose 0.

In the simplest assumed equation f(x) = 1 + x, x would have to = 0.

If we're looking at this graphically, y=1 (remember y=f(x)) graphed is a straight line that never crosses the x axis, which would mean there's no possible x value that would work for that equation.

Also, depending on what level math you're in, you may not even be working with undefined answers yet, in which case, your best answer would again be 0.

Hope this helped!

7 0

3 years ago

Does anyone know this????

Llana [10]

Picture isn't loading can you write it down?

3 0

3 years ago

Given:• PQRS is a rectangle.• mZ1 = 50°Р21SRWhat is mZ2?130°85°70°65°

Over [174]

To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"

Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.

Now, we have to recall that:

- the base angles of any isosceles triangle are equal. This is a fact, and this means that the angles

- also the sum of all the angles in any triangle is 180 degrees

Now, considering the isosceles triangle OQR, we have that:

$\angle OQR+\angle ORQ+\angle ROQ=180^o$

Now, since the figure already shows that angle $m\angle2+\angle ORQ+50^o=180^o$ Now, since we have established that the base angles $m\angle2+m\angle2+50^o=180^o$ we can now solve the above equation for m<2 as follows:

$\begin{gathered} m\angle2+m\angle2+50^o=180^o \\ \Rightarrow2m\angle2+50^o=180^o \\ \Rightarrow2m\angle2=180^o-50^o \\ \Rightarrow2m\angle2=130^o \\ \Rightarrow m\angle2=\frac{130^o}{2}=65^o \end{gathered}$

Therefore, the correct answer is: option D

7 0

1 year ago