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mixer [17]
3 years ago
5

Help plead i dont get this

Mathematics
1 answer:
professor190 [17]3 years ago
8 0
Find the percent of the circle

r=radius of circle
then r=1/2 of the diagonal of the square
use some pythagoran theorme

45,45,90 triangle
(r√2)/2=1/2 of a side
r√2 is one side
square it
2r²=square

area of circle is pir²
percent it is is

square/circle=
(2r²)/(pir²)=
2/pi= about
0.636
about 64% that it is in the square

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1+231 divided by 223,123
guapka [62]

Answer:

1.0010353034

Step-by-step explanation:

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2 years ago
Which system of equations can be used to find the roots of the equation 4x^5-12x^4+6x=5x^3-2x?
Sveta_85 [38]
^{(1)}\ \ 4x^5-12x^4+6x=5x^3-2x\ \ ^{(2)}\\\\  \left\{\begin{array}{ccc}y=4x^5-12x^4+6x\ \ \ ^{(1)}\\y=5x^3-2x\ \ \ ^{(2)}\end{array}\right


Answer: system nr 4.
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3 years ago
Find the length of AC
mina [271]
The answer is 8 yd.. :)
5 1
3 years ago
Write an equation for the line that is parallel to y =<br>-2x and passes through the point (0, -7).​
crimeas [40]

Answer:

y=-2x-7

Step-by-step explanation:

y=-2x

y-y1=m(x-x1)

y-(-7)=-2(x-0)

y+7=-2(x)

y+7=-2x

y=-2x-7

4 0
2 years ago
Compare the temperature change for the two masses of cold water (50 grams and 100 grams) when the same amount of hot water was a
Vesnalui [34]

Answer:

Step-by-step explanation:

All other things being equal (and there are a lot of other things) the 50 gram mass will show a larger temperature

increase than the 100 gram mass.

Why?

The formula is the same from both masses of water (50 grams and 100 grams)

The amount of heat added is the same. (Instead of using hot water, we'll a hot plate on a very low temperature but above what they are now.).

We'll leave it on until we see a rise in temperature  delta(t1) = 10 degrees

mc delta(t) = m1 * c * delta(t1)

m = 100

m1 = 50 grams.

c is going to be divided out

we'll solve for the ratio of delta(t) / delta(t1)

100 * delta(t) = 50 (delta(t1)

100 * delta(t) = 50*10

delta(t) = 50*10/100

delta(t) = 5 degrees.

Though this may look rather convoluted, the result is telling us is that delta(t1) for the 50 gram mass is twice as big as as for the 100 gram mass.

The 100 gram mass only rises 5 degrees.

The 50   gram mass rises 10 degrees.

7 0
3 years ago
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