To get the maximum height, we first determine the time at which this maximum height is attained by differentiating the given equation and equating the differential to zero.
h(t) = -0.2t² + 2t
Differentiating,
dh(t) = -(0.2)(2)t + 2 = 0
The value of t is equal to 5. Substituting this time to the original equation,
h(t) = -0.2(5²) + 2(5) = 5 ft
Thus, the maximum height is 5 ft and since it will take 5 seconds for it to reach the maximum height, the total time for it to reach the ground is 10 seconds.
Answers: maximum height = 5 ft
time it will reach the ground = 10 s
Answer:
N, which is the increment is 4
Answer:
% Decrease = 11.45%
Step-by-step explanation:
Original Population = 5893
Expected Population = 5218
% Decrease = Original Population - Expected Population / Original population
% Decrease = (5893 - 5218 ) / 5893
% Decrease = 675/5893
% Decrease = 0.11454268
% Decrease = 11.454268%
% Decrease = 11.45% approximately.
Step-by-step explanation:
x²+4-4x+y²=3
x²+y²-4x+1=0
<h3>
Answer: 60</h3>
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Explanation:
Multiply the two values to get 4*15 = 60
Then divide by the GCF 1 to get 60/1 = 60. The GCF being 1 means the result hasn't changed.
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Another example would be: "Find the LCM of 6 and 8". We would first do 6*8 = 48, then divide by the GCF 2 to get 48/2 = 24. The LCM of 6 and 8 is 24.
