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Svetach [21]
3 years ago
7

A 170-lb man carries a 20-lb can of paint up a helical staircase that encircles a silo with radius 30 ft. The silo is 90 ft high

and the man makes exactly three complete revolutions. Suppose there is a hole in the can of paint and 8 lb of paint leaks steadily out of the can during the man's ascent. How much work is done by the man against gravity in climbing to the top
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

large man

Step-by-step explanation:

dinosaur

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A line has a slope of 1 and passes through the point (-8, -7). What is its equation in
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Step-by-step explanation:

y = 1x + c

-7 = 1(-8) + c

-7 = -8 + c

-7 + 8 = c

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y = 1x + 1 or

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A triangle has side lengths of ,m,3m,and 3m+3. what is the perimeter of the triangle
Galina-37 [17]

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5 0
4 years ago
Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Andre45 [30]

For this case, we must indicate which of the given functions is not defined forx = 0

By definition, we know that:

f (x) = \sqrt {x} has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative when x = 0.

While y = \sqrt {x + 2} if it is defined for x = 0.

f(x)=\sqrt[3]{x}, your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

y = \sqrt [3] {x-2} with x = 0: y = \sqrt [3] {- 2} is defined.

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Answer:

y = \sqrt {x-2}

Option b


6 0
3 years ago
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