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enot [183]
3 years ago
11

students at river view middle school are allowed to wear two different colors of uniform shirts. A survey of students at the sch

ool shows that a student is three times more likely to wear a red shirt than a white shirt. If a classroom has 24 students, how many students are likely to be wearing red?
Mathematics
1 answer:
Vladimir79 [104]3 years ago
5 0

Answer:

18 students are likely to be wearing red

Step-by-step explanation:

From the question, we know a student either wears red , or blue, with the probability of a student wearing red is 3 times more probable than wearing white.

So, let’s say out of the 24 students, x of them are wearing white. What this practically mean is that 3 * x = 3x of the students would be expected to be wearing red.

Now, adding the number of people wearing red and white together in terms of x, we have x + 3x = 4x

We equate this to 24; 4x = 24 and x = 24/4; x = 6

The number wearing red probably is 3 * x = 3 * 6 = 18 people

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3 years ago
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Suppose that a brand of lightbulb lasts on average 1730 hours with a standard deviation of 257 hours. Assume the life of the lig
Debora [2.8K]

Answer:

P [  1689  ≤   X  ≤  2267 ]  = 54,88 %

Step-by-step explanation:

Normal Distribution

Mean        μ₀  =  1730

Standard Deviation      σ  = 257

We need to calculate  z scores for the values   1689     and      2267

We apply formula for z scores

z =  ( X -  μ₀ ) /σ

X = 1689     then

z = (1689 - 1730)/ 257      ⇒ z = - 41 / 257

z  = -  0.1595

And from z table we get  for  z =  - 0,1595

We have to interpolate

        - 0,15          0,4364

        - 0,16          0,4325

Δ  =   0.01           0.0039

0,1595  -  0,15  =  0.0095

By rule of three

0,01                  0,0039

0,0095                 x ??      x  =  0.0037

And    0,4364  -  0.0037  = 0,4327

Then    P [ X ≤ 1689 ]  =  0.4327     or    P [ X ≤ 1689 ]  = 43,27 %

And for the upper limit  2267  z  score will be

z  =  ( X - 1730 ) / 257       ⇒  z =  537 / 257

z  =  2.0894

Now from z table   we find  for score   2.0894

We interpolate and assume  0.9815

P [ X ≤ 2267 ]  =  0,9815

Ths vale already contains th value of   P [ X ≤ 1689 ]  =  0.4327

Then we subtract  to get    0,9815  -  0,4327   = 0,5488

Finally

P [ 1689  ≤   X  ≤  2267 ]  =  0,5488  or  P [  1689  ≤   X  ≤  2267 ]  = 54,88 %

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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