Answer:
15.8 or 15 4/5
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Answer:
h(x)= x^2+11x+30
Step-by-step explanation:
A quadratic function is in the form h(x) = ax^2 + bx + c.
Since the zeros are -6 and -5, take the opposite signs and add them to the variable x separately.
It should look like this: h(x)= (x+6)(x+5)
Since this is the factored form, we have to solve this equation further.
h(x)= (x+6)(x+5)
h(x)= x^2+6x+5x+30
h(x)= x^2+11x+30
Answer:
three u's and an I
Step-by-step explanation:
3×3=9
that's 3 u's so if you add an I its 10
Answer:
a) For the 90% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
b) For the 99% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Step-by-step explanation:
Previous concepts
The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."
Solution to the problem
Part a
For the 90% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
Part b
For the 99% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got: