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dedylja [7]
3 years ago
14

two supplementary angles consist of one acute angle and one obtuse angle. a)always b)sometimes c) never

Mathematics
1 answer:
mel-nik [20]3 years ago
4 0

the sum of supplementary angles equals 180°

you can have an acute angle (less than 90°) + an obtuse angle (greater than 90°) equal to 180°

But you can also have a right angle (equal to 90°) + another right angle equal to 180°

Answer: (b) sometimes

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What is the difference of the polynomials? (â€""2x3y2 4x2y3 â€"" 3xy4) â€"" (6x4y â€"" 5x2y3 â€"" y5) â€""6x4y
zlopas [31]

Polynomial-An expression of two or more algebraic terms, which is the sum or difference of the several terms with having different power of the only variable. The difference between the given polynomials is

=-2x^3y^2 + 9x^2y^3-3xy^4-6x^4y+y^5

Given-

We have given two function of variable <em>x </em>and <em>y</em>

(-2x^3y^2 + 4x^2y^3-3xy^4)

(6x^4y-5x^2y^3-y^5)

<h3>Polynomial</h3>

An expression of two or more algebraic terms, which is the sum or difference of the several terms with having different power of the only variable.

Now we have to subtract the two equations to find the difference,

(-2x^3y^2 + 4x^2y^3-3xy^4)-(6x^4y-5x^2y^3-y^5)

Multiply the sign into the bracket to open the bracket and further solution,

=-2x^3y^2 + 4x^2y^3-3xy^4-6x^4y+5x^2y^3+y^5

Arrange the similar terms in the same groups,

=-2x^3y^2 + (4x^2y^3+5x^2y)-3xy^4-6x^4y+y^5=-2x^3y^2 + 9x^2y^3-3xy^4-6x^4y+y^5

Hence, the difference between the given polynomials is=-2x^3y^2 + 9x^2y^3-3xy^4-6x^4y+y^5

For more about the polynomials, follow the link below-brainly.com/question/17822016

5 0
3 years ago
PLZ HELP I WILL MARK BRAINLYST
Gre4nikov [31]
c - 7 \geqslant - 3 \\ c \geqslant - 3 + 7 \\ c \geqslant 4
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