The area of a rectangle is (length) times (width).
So you have to find a pair of numbers that multiply to produce 6 .
If you only stick to whole numbers, then I don't think there are three
different ones. You're going to need one pair that multiply to 6 and
are not both whole numbers.
After I explain how to solve problems, I hate to give answers. But with
all due respect, I have a feeling that I haven't nudged you enough yet
for you to use my explanation to find the answers on your own.
So here are some answers:
1 and 6
2 and 3
and sets of dimensions that are not both whole numbers, like
0.6 and 10
1.2 and 5
1.25 and 4.8
1.5 and 4
2.4 and 2.5
Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
Answer:
all work is shown/pictured
I did wow owner was very rude