Could you give more detail
Answer:
Step-by-step explanation:
cotx/cscx=cosx
Start on the left side.
cos(x) csc(x)
Apply the reciprocal identity to csc (x) .
cos(x) 1/sin(x)
Simplify
cos(x) 1/sin(x)cos(x)/sin(x)
Rewrite cos(x)/sin(x) as cot(x) .
cot(x)
Because the two sides have been shown to be equivalent, the equation is an identity.
cos(x) csc(x)=cot(x) is an identity
cot(x)−tan(x)/sin(x)cos(x)=csc^2(x)−sec^2(x) is an identity
You are correct :)
5(p+5) + 6(p+6)
First step: Distribute (PEMDAS --> Parenthesis)
5p + 25 + 6p + 36 Now, combine like terms
11p + 61
Thus, the answer is 11p + 61
The area will be half the product of the lengths of AB and CD.
|AB| = √((6-1)² +(-2-3)²) = 5√2
|CD| = √((5-2)² +(5-2)²) = 3√2
Area = (1/2)*(5√2)*(3√2) = (1/2)*(15*2) = 15
The appropriate choice is ...
D: 15 square units
