Step-by-step explanation:
x= -7 y=0
x= -3 y =-6
y =mx+b
b=-7
-6= -3m -7
-3m = 1
m= -1/3
y= -x/3 -7
GIVING BRAINLIEST!!
1 answer:
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To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
![\sqrt[3]{216 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20)
2. Rewriting the expression we have:
![\sqrt[3]{6^3 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B6%5E3%20x%5E%7B27%7D%20%7D%20)
3. You have that
and the exponent 
are divisible by index 
. Therefore, you have:
![\sqrt[3]{216 x^{27} } =6 x^{9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20%3D6%20x%5E%7B9%7D%20)
Therefore, as you can see,
the answer is the option, which is:
1. You have the following expression given in the problem above:
2. Rewriting the expression we have:
3. You have that
Therefore, as you can see,
the answer is the option, which is:
Answer:
4y = x - 17
Step-by-step explanation:
First off, in the equation given : 2x + 5y = 6 , make y the subject of the formula which will give y = +
which make the gradient, m, the coefficient of x =
. Since the line we're looking for is parallel to the one we were given, their respective gradients would be the same. (If they were perpendicular, the gradient of the new line would be a negative inverse of the given line)
Then you proceed to use the one-point formula : y - y₀ = m(x - x₀), where y₀ = 3 and x₀ = 5 from the point it goes through (5, 3)
y - 3 = (x - 5); y - 3 =
-
; y =
-
+3
y = -
; y =
; 4y = x - 17