<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
Answer:42.55$
Step-by-step explanation:
Answer:
Options 1, 3 and 4 are true
Step-by-step explanation:
The legs EF and DF of the right triangle DEF have lengths of 24 units and 7 units, respectively. By the Pythagorean theorem,
Find trigonometric functions:
Thus, options 1, 3 and 4 are true
Answer:
Step-by-step explanation:
Yay graphs!!!!!!
Okay so as you should know, the structure of a linear equation is y = mx + b.
B is the y-intercept
so the first thing to do is mark the coordinates (0,1) as the y-intercept
Now the slope is 1/4 x
this is also known as rise/run
A simpler way to do that is from (0,1) move up 1 and over four and place a point there
The coordinate should be (4,1)
Then draw a line through the two points
Convert percent into a decimal by moving the percent sign two places to the left.
39% => 0.39
'Of' in math means multiply.
0.39 * 50 = 19.5