Looking at the set, we are given 18 elements. 17 is prime; it has only two factors: 1 and 17, since 1•17=17. So, the question is really asking what is the probability the numbers 1 or 17 is chosen. As mentioned earlier, 17 is prime, so there are two possible choices: 1 and 17.
P (probability) = possible outcomes / total outcomes
It is important to note that these events are “or” events, meaning that the probability can only be determined by choosing a 1 or a 17; you can’t randomly chose a 1 and 17 at the same time. So, the formula is:
P(A or B) = P(A) + P(B)
All this is saying is that given two possible outcomes, the probability occurs independent of each event; they don’t occur at the same time.
P(1 or 17) = P(1)/18 + P(1)/18
P(1 or 17) = 2/18
Since 17 is prime, it’s two and only factors are 1 and 17. The probability of randomly choosing a 1 or 17 is 2/18, meaning that there are 2 elements in the set out of a possible 18 elements that can be randomly chosen.
2/18 simplifies to 1/9
So, your answer is 1/9
Answer:
6
Step-by-step explanation:
2/3 of 54 is 36. 1/6 of 36 is 6.
Answer:
2
Step-by-step explanation:
the - means you have to subtract to add. so subtract 3 over 4 and you get 2
I don’t know answer but I use gauthmath to help me with math u may as well use it and u can use this code P9EJ5H thank me later non
Answer:
D. 0.64
Step-by-step explanation:
The reason I got this answer is because the problem tells us that there is a success rate of .36, so you would subtract .36 from 1 to get .64. The success rate and failure rate should always be equal to 1.
