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3 years ago

Find the tenth term in the following geometric sequence. 8, 4, 2, 1, . . .

Mathematics

1 answer:

Marrrta [24]3 years ago

7 0

Answer:

c) 0.0156

Step-by-step explanation:

The general term a[n] of a geometric sequence is given in terms of the first term a[1] and common ratio r as ...

a[n] = a[1]r^(n-1)

The given sequence has an initial term of a[1]=8 and a common ratio of 4/8=1/2. Then the general term is ...

a[n] = 8(1/2)^(n-1)

The 10th term is then ...

a[10] = 8(1/2)^(10-1) = 8(1/2)^9 = 8/512

a[10] = 0.015625 ≈ 0.0156

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Ratling [72]

Answer: point estimate = 3.88

Margin of error = 0.63

Step-by-step explanation:

Confidence interval is written in the form,

(Point estimate - margin of error, Point estimate + margin of error)

The sample mean, x is the point estimate for the population mean. Let m represent the margin of error. Since the confidence interval is given as (3.25 , 4.51), it means that

x - m = 3.25

x + m = 4.51

Adding both equations, it becomes

2x = 7.76

x = 7.76/2

x = 3.88

Substituting x = 3.88 into x + m = 4.51, it becomes

3.88 + m = 4.51

m = 4.51 - 3.88

m = 0.63

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3 years ago

If x=6 is the only x-intercept of the graph of a quadratic equation, which statement best describes the discriminant of the equa

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3 years ago

The amount of money,y, in cash box after x tickets are purchased for carnival games. The slope of the line is 1/4 and the y-inte

victus00 [196]

Amount of money received when x tickets are sold=$Y

Number of tickets sold=X

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y = m x + c,

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3 years ago

In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older

earnstyle [38]

Answer:

Step-by-step explanation:

In the past, mean of age of employees

i.e. $\mu = 40$

Recently sample was taken

n = sample size = 60

Mean of sample = 45

Std dev of sample s = 16

$H_0: \bar x = 40\\H_a: \bar x >40$

(Right tailed test)

Since only population std deviation is known we can use t test only

Std error = $\frac{s}{\sqrt{n} } \\=\frac{16}{\sqrt{61} } \\=2.049$

Mean difference = 45-40 =5

Test statistic t= $\frac{5}{2.049} \\=2.441$

df = 60

p value =0.008739

Since p < 0.05 we reject null hypothesis

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3 years ago

Which transformation of x?

Nady [450]

Its C! Hope this helps and can you mark me as brainliest :))

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