Option A. All the real values of x where x < -1
Procedure
Solve the inequality:
(x -3)(x+1)>0
That happens in two cases.
1) When both factors >0
x-3>0 and x+1>0
x>3 and x >-1
The intersection is x >3
2) When both factors <0
x-3<0 and x+1<0
x<3 and x<-1
the intersection is x<-1.
We have obtained that the function is positive for the intervals x < -1 and x > 3. But in one of those intervals the function is decresing and in the other is increasing.
You can recognize that the function given is a parabola and, because the coefficient of the quadratic term is positive, the parabola opens upward. Then the function is decreasing in the first interval and increasing in the second interval.
Answer:
hindi sulotion kung hindi man sorry nalang
walarin akong alam diyaan
Step-by-step explanation:
im sosory
Answer:
h=9
Step-by-step explanation:
18h+30=192
18h=162
h=9
Answer:
y=3/2x+11/2
Step-by-step explanation:
Hello! Sorry I just saw this
Anyways, let's continue
first, we need to find the equation of the line with the one that is (-2,-4) and (2,2)
first, we need to find the slope
the equation for slope is y2-y1/x2-x1
so let's label the points
x1=-2
y1=-4
x2=2
y2=2
now plug it in
2-(-4)/2-(-2)=6/4=3/2
now, let's turn it into a line
the point-slope form is y-y1=m(x-x1) (m=slope)
now, plug it in
y-(-4)=3/2(x-(-2))
simplify to
y+4=3/2(x+2)
turn into y=mx+b format
y+4=3/2x+3
subtract 4 on both sides
y=3/2x-1
Now for the line that is parallel.
Parallel lines have the same slopes, so you automatically know that the new line will be y=3/2x+b
To make sure (-3,1) is a solution to the point, put 1 as y and -3 as x
1=3/2(-3)+b
1=-9/2+b
add 9/2 on both sides
b=11/2 or 5.5
now, put it into the equation
y=3/2x+11/2
Hope this helps!
