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3 years ago

What are these fractions in simplest form: 14/19, 4/32, 2/9, 23/31

Mathematics

1 answer:

umka21 [38]3 years ago

5 0

14/19 is in simplest form

4/32 turns to 2/16 which turns to 1/8,

2/9 is in simplest form

23/31 is in simplest form

answer is 12/19, 1/8, 2/9, and 23/31

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Let f(x)= x^2-4x-c. Find a nonzero value of c such that f(c)=c.

Dimas [21]

Answer:

The nonzero value of c will be:

$c = 6$

Step-by-step explanation:

Given the function

$f\left(x\right)=\:x^2-4x-c$

$f\left(c\right)=\:c^2-4c-c$

$f(c) = c$

$c=\:c^2-4c-c$

switching the sides

$c^2-4c-c=c$

subtract c from both sides

$c^2-4c-c-c=c-c$

$c^2-6c=0$

$c\left(c-6\right)=0$

Using the zero factor principle

$\:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$c=0\quad \mathrm{or}\quad \:c-6=0$

so, the solutions to the quadratic equations are:

$c=0,\:c=6$

Therefore, a nonzero value of c will be:

$c = 6$

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3 years ago

The vertices of ABC are A(-3,5), B(-2,3), and C(-5,3). If ABC is reflected across the y-axis to produce the image A'B'C', find t

Nat2105 [25]

Answer:

$C' =(5,3)$

Step-by-step explanation:

Given

$A = (-3,5)$

$B = (-2,3)$

$C = (-5,3)$

Reflection across y-axis

Required

Find C'

For reflection across y-axis, the rule is:

$(x,y) \to (-x,y)$

So, the image of C is:

$(-5,3) \to (-(-5),3)$

$(-5,3) \to (5,3)$

Hence:

$C' =(5,3)$

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motikmotik

Answer:

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Step-by-step explanation:

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g + 9 - 9 = 70 - 9

g = 61.

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svp [43]

Answer:

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Step-by-step explanation:

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