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3 years ago

How many 1/8 pound servings of walnuts, s , are in 3/4 pound of walnuts?

Mathematics

2 answers:

aliya0001 [1]3 years ago

7 0

1/8 s = 3/4
2/16 s = 12/16 (multiply each side by 16)
2s = 12 (divide each side by 2)
s = 6

Ann [662]3 years ago

7 0

Answer:

6 servings.

Step-by-step explanation:

We have to calculate the servings of $\frac{1}{8}$ pounds of walnuts in $\frac{3}{4}$ pounds of walnuts.

Let s be the number of servings of $\frac{1}{8}$ pounds of walnuts.

Then $(\frac{1}{8})$ × s = $\frac{3}{4}$

s = $\frac{(\frac{3}{4} )}{(\frac{1}{8} )}$

= $\frac{3}{4}$ × $\frac{8}{1}$

s = 6

Therefore, there are 6 servings.

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3 years ago

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Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

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The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

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Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :

For the first parenthesis:

$x^{2}+6x+b^{2}$

We can rewrite this as:

$x^{2}+2(3)x+b^{2}$

Hence in this case $b=3$ and $b^{2}=9$ :

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We can rewrite this as:

$y^{2}-2(4)y+b^{2}$

Hence in this case $b=-3$ and $b^{2}=9$ :

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Then, equation (5) is rewritten as follows:

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Rearranging:

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At this point we have the circle equation in the center radius form $(x-h)^{2} +(y-k)^{2}=r^{2}$

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