The fraction 6/11 is equivalent to the fraction of 18/33. They both have the same value. Simply multiply both the numerator and denominator by 3 to the fraction of 6/11 to get the new equivalent one.
Answer:
a. square root is y = 
b. linear is y = x
c. cubic is 
d. quadratic is 
e. reciprocal squared is 
f. absolute value is y = |x|
g. reciprocal is 
h. cube root is ![y = \sqrt[3]{x}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7Bx%7D)
Step-by-step explanation:
18-8 is equivalent given that is a ratio you're talking about
The blank space is found by dividing 36a^2 by 12, which is equal to 3a^2
To get to this answer you need to
1. divide the both sides of the equation by 12.
2. subtract 2b^2 from both sides.
You will see that the blank space equals 3a<span>^2 then</span>
Answer:
x² -3/4x +1/4 = 0
Step-by-step explanation:
Consider the two equations in factored and expanded forms:
(x -p²)(x -q²) = x² -(p²+q²)x +p²q² = 0 ⇒ p²+q² = 1, p²q² = 16
and
(x -1/p)(x -1/q) = x² -(1/p+1/q)x +1/(pq) = 0
Consider the squares of the sum and product of roots:
constant term: (1/(pq))² = 1/(p²q²) = 1/16 ⇒ 1/(pq) = √(1/16) = 1/4
x-term: (1/p +1/q)² = (p +q)²/(pq)² = (p² +q² +2pq)/(p²q²)
= (p² +q²)/(p²q²) +2/(pq)
= 1/16 +2/√16 = 9/16 ⇒ (1/p +1/q) = √(9/16) = 3/4
Then the equation with roots 1/p and 1/q is ...
x² -3/4x +1/4 = 0
