Answer: The correct option is (B) f(q) = 2q + 3.
Step-by-step explanation: The given equation representing a function is
We are to write the equation in function notation with 'q' as independent variable.
From equation (i), we have
So, 's' can be represented as a function of 'q'. Hence, we can write
Therefore, we have
Thus, (B) is the correct option.
Answer:
11 is your corect awnser neess to be 20 characters
Step-by-step explanation:
5 times 11 is 55
Answer:
Use the method for solving Bernoulli equations to solve the following differential equation.
StartFraction dy Over dx EndFraction plus StartFraction y Over x minus 9 EndFraction equals 5 (x minus 9 )y Superscript one half
Step-by-step explanation:
Use the method for solving Bernoulli equations to solve the following differential equation.
StartFraction dy Over dx EndFraction plus StartFraction y Over x minus 9 EndFraction equals 5 (x minus 9 )y Superscript one half
Answer: 6,520 miles per year
Step-by-step explanation:
They had driven the car for 53,790 miles in 8.25 years.
The average number of number of miles driven per year is:
= 53,790 / 8.25 years
= 6,520 miles per year
<em>They drove an average of 6,520 miles per year.</em>
Answer:
(A) Set A is linearly independent and spans 
. Set is a basis for .
Step-by-Step Explanation
<u>Definition (Linear Independence)</u>
A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.
<u>Definition (Span of a Set of Vectors)</u>
The Span of a set of vectors is the set of all linear combinations of the vectors.
<u>Definition (A Basis of a Subspace).</u>
A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.
Given the set of vectors ![A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right)](https://tex.z-dn.net/?f=A%3D%20%5Cleft%28%5Cbegin%7Barray%7D%7B%5Bc%5D%5Bc%5D%5Bc%5D%5Bc%5D%7D1%20%26%200%20%26%200%20%26%200%5C%5C%200%20%26%201%20%26%200%20%26%201%5C%5C%200%20%26%200%20%26%201%20%26%201%5Cend%7Barray%7D%20%5Cright%29%20)
, we are to decide which of the given statements is true:
In Matrix ![A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right)](https://tex.z-dn.net/?f=A%3D%20%5Cleft%28%5Cbegin%7Barray%7D%7B%5Bc%5D%5Bc%5D%5Bc%5D%5Bc%5D%7D%281%29%20%26%200%20%26%200%20%26%200%5C%5C%200%20%26%20%281%29%20%26%200%20%26%201%5C%5C%200%20%26%200%20%26%20%281%29%20%26%201%5Cend%7Barray%7D%20%5Cright%29%20)
, the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans .
Therefore Set A is linearly independent and spans . Thus it is basis for .
